Chapter 10, Problem 10.19P

Interpretation Introduction

Interpretation:

To find the fugacity, of cyclopentane at 110 ⁰C and 275 bar.

Concept Introduction :

For the given conditions, we first find Reduced Temperature, T_r and Reduced Pressure, P_r$T_r=\frac{T}{T_C}$

and

  $P_r=\frac{P}{P_C}$

Fugacity Coefficient can be found by Virial equation

  $\varphi =\exp \left[\frac{P_r}{T_r}(B^0+\omega B^1\right]$

where the values of $B^0$ and $B^1$ are found as below,

  $B^0=0.083-\frac{0.422}{T_r^{1.6}}$

  $B^1=0.139-\frac{0.172}{T_r^{4.2}}$

  $V^{sat}=V_c{Z}_c^{{\left(1-T_r\right)}^{2/7}}$

  $f=\left[\varphi \times P_{sat}\times \exp \left[\frac{V_{sat}\times (P-P_{sat})}{R\times T}\right]\right]$

Where,

R = Universal Gas constant = 8.314×10-5 m³bar/mol.K

T = Temperature = 110 ⁰C = 383.15 K

T_c = Critical Temperature

P_c = Critical Pressure

  $\varphi$ = Fugacity Coefficient = $\frac{f}{P}$

P = Pressure = 275 bar

f = Fugacity

P_sat = Vapor pressure = 5.267 bar

ω = Acentric factor