Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH 3 I, (b) ClF 3 , (c) H 2 S, (d) SO 3 , (e) SO 4 2 − .

Question

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Answer 1

Textbook Question

Chapter 10, Problem 10.10QP

Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH₃I, (b) ClF₃, (c) H₂S, (d) SO₃, (e) SO 4 2 − .

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

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Answer 2

Textbook Question

Chapter 10, Problem 10.10QP

Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH₃I, (b) ClF₃, (c) H₂S, (d) SO₃, (e) SO 4 2 − .

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 10, Problem 10.10QP

Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH₃I, (b) ClF₃, (c) H₂S, (d) SO₃, (e) SO 4 2 − .

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

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Answer 4

Textbook Question

Chapter 10, Problem 10.10QP

Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH₃I, (b) ClF₃, (c) H₂S, (d) SO₃, (e) SO 4 2 − .

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

Answer 8

(a)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 1 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 5 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer 13

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Answer 14

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

Answer 15

(b)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 7 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 11 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer 20

Answer to Problem 10.10QP

(b)

Trigonal planar

Answer 21

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

Answer 22

(c)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 13 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 17 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer 27

Answer to Problem 10.10QP

(c)

Bent shaped

Answer 28

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

Answer 29

(d)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 19 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 23 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer 34

Answer to Problem 10.10QP

(d)

Trigonal planar

Answer 35

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

Answer 36

(e)

Expert Solution

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

The first step is to draw the correct Lewis structure for the molecule.
Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 25 will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type will have shape like trigonal planar, typewill have shape like tetrahedral or square planar, type will have trigonal bipyramidal and EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 29 will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer 41

Answer to Problem 10.10QP

(e)

Tetrahedral

Answer 42

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

EBK CHEMISTRY, Chapter 10, Problem 10.10QP , additional homework tip 30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom