Explanation: Cars propagate the tollbooths of length 75 km at a speed of 100km/hr and the tollbooth takes 12 seconds to service each car. There are 10 cars which take 12 × 10 = 120 seconds or 2 minutes to cross a tollbooth. At first tollbooth, the propagation delay of the cars is 45 minutes and reaches the second tollbooth after 2 + 45 = 47 minutes. The process repeats with second and third tollbooths and also takes 120 seconds or 2 minutes time for service. Finally, the total propagation delay is calculated using following formula the propagation delay = time taken for service in first tollbooth+ time taken to reach second tollbooth

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Chapter 1, Problem P5P

a.

Explanation of Solution

Cars propagate the tollbooths of length 75 km at a speed of 100km/hr and the tollbooth takes 12 seconds to service each car. There are 10 cars which take 12 × 10 = 120 seconds or 2 minutes to cross a tollbooth.

At first tollbooth, the propagation delay of the cars is 45 minutes and reaches the second tollbooth after 2 + 45 = 47 minutes.

The process repeats with second and third tollbooths and also takes 120 seconds or 2 minutes time for service.

Finally, the total propagation delay is calculated using following formula

the propagation delay = time taken for service in first tollbooth+time taken to reach second tollbooth

b.

Explanation of Solution

Cars propagate the tollbooths of length 75 km at a speed of 100km/hr and the tollbooth takes 12 seconds to service each car. There are 8 cars which take 12 × 8 = 96 seconds to cross a tollbooth.

At first tollbooth, the propagation delay of the cars is 45 minutes and reaches the second tollbooth after 46 minutes and 36 seconds.

The process repeats with second and third tollbooths and also takes 96 seconds time for service.

Finally, the total propagation delay is calculated using following formula

the propagation delay = time taken for service in first tollbooth+time taken to reach second tollbooth +</

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