As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
Solution Summary: The author explains that the scientific system of measurement is called the systeme internationale d’Unites and it is abbreviated SI.
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s2. The unit of mass this is the slug, which is 14.59 kg. Thus,
BE unit of force = 1 pound =
(
slug
)
(
ft / s
2
)
Use thisinformation to confirm that
BE unit of force = 4
.45×SI unit of force
Relative Intensity
Part VI. consider the multi-step reaction below for compounds
A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
100
HS-NJ-0547
80
60
31
20
S1
84
M+
absent
10
30
40
50
60
70
80
90
100
100-
MS2016-05353CM
80-
60
40
20
135 137
S2
164 166
0-m
25
50
75
100
125
150
m/z
60
100
MS-NJ-09-43
40
20
20
80
45
S3
25
50
75
100
125
150
175
m/z
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