Chapter 1, Problem 89E

Interpretation Introduction

Interpretation:

The density of liquid and gaseous nitrogen and the volume of the liquid nitrogen are given. The fraction of air that is displaced in the room of given dimensions by the gaseous nitrogen is to be calculated.

Concept introduction: The conversion of one liter into milliliter is done as,
  $\text{1}\text{L}={10}^3\text{mL}$

The mass is calculated by the formula,
  $\text{Mass}=\text{Density}\times \text{Volume}$

The volume is calculated by the formula,

  $\text{Volume}=\frac{\text{Mass}}{\text{Density}}$

The conversion of one millimeter into ${\text{m}}^{\text{3}}$ is done as,
  $1\text{mL}={10}^{-6}{\text{m}}^{\text{3}}$

To determine: The fraction of air in the room that is displaced by the gaseous nitrogen.