The Solar System
10th Edition
ISBN: 9781337672252
Author: The Solar System
Publisher: Cengage
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Chapter 1, Problem 3SP
To determine
The celestial body whose radius is approximately equal to 100 times Sun’s diameter.
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An astronomical unit (AU) is defined as the average distance between
the solar system and Alpha Centauri
the Earth and the Moon
the Milky Way Galaxy and the Andromeda Galaxy
the Earth and the Sun
Raising a number in scientific notation to a power is easy:
(5 x 105)² = (5)² x (105)² = 5 x 5 x 105 x 105 = 25 x 10(5 × 2) = 25 x 1010 = 2.5 x 101¹1
Keeping this in mind, what is the volume of the sun in km³? The radius of the sun is about 7 x 105 km, and the volume of a sphere is 4/3 x Pi x R³. (Use 3.14 for Pi, and enter your answer with two decimal places).
km³
3
What is the average density of the Sun? Density = mass / volume. The mass of the sun is 2.0x10³0 kg.
kg/km³
The nearest star to our sun is Proxima Centauri, at a distance of 4.3 light-years from the Sun. A light-year is the distance that light travels in one year (365 days). How far away, in kilometers, is Proxima Centauri from the Sun?Express your answer using two significant figures.
Chapter 1 Solutions
The Solar System
Ch. 1 - Prob. 1RQCh. 1 - What is the largest dimension of which you have...Ch. 1 - What is the difference between the Solar System,...Ch. 1 - What is the difference between the Moon and a...Ch. 1 - Prob. 5RQCh. 1 - Why are light-years more convenient than miles,...Ch. 1 - Why is it difficult to detect planets orbiting...Ch. 1 - Prob. 8RQCh. 1 - What is the difference between the Milky Way and...Ch. 1 - What are the Milky Way Galaxys spiral arms?
Ch. 1 - Prob. 11RQCh. 1 - Where are you in the Universe? If you had to give...Ch. 1 - Prob. 13RQCh. 1 - Prob. 14RQCh. 1 - Prob. 15RQCh. 1 - How do we know? How does the scientific method...Ch. 1 - The equatorial diameter of Earth is 7928 miles. If...Ch. 1 - Prob. 2PCh. 1 - One astronomical unit (AU) is about 1.5 108 km....Ch. 1 - A typical galaxy is shown on the first page of the...Ch. 1 - Prob. 5PCh. 1 - Venus orbits 0.72 AU from the Sun. What is that...Ch. 1 - Light from the Sun takes 8 minutes to reach Earth....Ch. 1 - The Sun is almost 400 times farther from Earth...Ch. 1 - If the speed of light is 3.0 × 105 km/s, how many...Ch. 1 - Prob. 10PCh. 1 - Prob. 11PCh. 1 - Prob. 12PCh. 1 - How many galaxies like our own would it take if...Ch. 1 - Arrange the following in order of increasing size:...Ch. 1 - Arrange the following in order of increasing...Ch. 1 - Prob. 3SPCh. 1 - Prob. 4SPCh. 1 - Look at the center of Figure 1–4. Approximately...Ch. 1 - Look at Figure 1-6. How can you tell that Mercury...Ch. 1 - Prob. 3LLCh. 1 - Look at Figure 1-9. Would you say that the...Ch. 1 - Prob. 5LLCh. 1 - Prob. 6LL
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The distance from the Sun to the nearest star is about 4 1016 m. The Milky Way galaxy (Fig. P1.31) is roughly a disk of diameter 1021 in and thickness 1019 m. Find the order of magnitude of the number of stars in the Milky Way. Assume the distance between the Sun and our nearest neighbor is typical. Figure P1.31 The Milky Way galaxy.arrow_forwardArrange the following in order of increasing size: Earth; the Sun; Earths orbit around the Sun; the Moon; you; the Milky Way Galaxy; the Moons orbit around Eartharrow_forwardThe light a planet receives from the Sun (per square meter of planet surface) decreases with the square of the distance from the Sun. So a planet that is twice as far from the Sun as Earth receives (1/2)2=0.25 times (25%) as much light and a planet that is three times as far from the Sun receives (1/3)2=0.11 times (11%) as much light. How much light is received by the moons of Jupiter and Saturn (compared to Earth), worlds which orbit 5.2 and 9.5 times farther from the Sun than Earth?arrow_forward
- How Do We Know? How can a scientific model be useful if it is not a true description of nature?arrow_forwardThe distance light travels in one second(one light-second) is about 1.86×10⁵ mi. Saturn is about 475 light-seconds from the sun. About how many miles from the sun is Saturn?arrow_forwardWrite the following measurements in scientific notation. All answers should be written up to hundredths place. Follow the rules in rounding off numbers. Quantity Measurement Scientific notation 1. diameter of the sun 1391400 km 2. Speed of light 2997792458 m/s 3. distance of the earth from the sun 149597870700 m 4. size of bacteria 0.0005 m 5. diameter of proton 0.000 000 000 001 mmarrow_forward
- Which of these correctly compares the masses of different objects in the universe? O A moon has less mass than a star and more mass than the planet it orbits O A planet has less mass than a galaxy and more mass than a star it orbits O A galaxy has less mass than a moon and more mass than a planet O A star has less mass than a galaxy and more mass than a planetarrow_forwardWhat would the angle between the Sun and the Earth be if the solar system were viewed from a distance of 1 pc?arrow_forwardO O o O O 2. 2536?module_item_id3D3790194 1 dozen = 12 things 1 day 24 hours 1 mile 5280 feet 1 meter 100 centimeters 1 year 365 days 1 six-pack = 6 cans 1 hour = 60 minutes 12 inches = 1 foot 1000 meters = 1 kilometer 1 case 24 cans 1 minute = 60 seconds 1 inch = 2.54 centimeters %3D 1 cup 8 ounces 1 box of Bisquick contains 96 ounces of pancake mix %3D 1. Billy has trouble with math, and his answer is "10" to the following question, "How 120 dozen?" a. What is the correct answer? b. What advice can you give Billy to help him do the calculation correctly? If I want 72 cans of soda, how many six-packs should I buy? 3. How many cases of soda should be bought if 8 dozen soda cans are wanted? 4. One million seconds are how many days? vork (hand-written, typed, or drawn on paper or on a computer).arrow_forward
- Some interstellar Properties. Use excel calculator to fill in the missing figures. 1 ly = 365 × 24 × 60 × 60 × 300, 000km/s = 9.46 × 10^12 kmarrow_forwardPlease answer with stepsarrow_forwardEarth is about 150 million kilometers from the Sun (1 Astronomical Unit, or AU), and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Using these two facts and the inverse square law for light, determine the apparent brightness that we would measure for the Sun if we were located at the following positions. a) At the orbit of Jupiter (780 million km from the Sun).arrow_forward
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