Given that three pennies and two dimes are equivalent to $0 .23 . You have 636 .3 g of pennies and each penny is 3 .03 g and each dime is 2 .29 g . Each piece of candy weighs 10.23 g . Using this data the following calculations have to be done – (a) Number of pennies you have (b) Number of dimes you need to buy as many candies as possible (c) Weight of all the dimes (d) Number of candy pieces you could buy (e) The weight of the total number of candies that u bought as described above.
Given that three pennies and two dimes are equivalent to $0 .23 . You have 636 .3 g of pennies and each penny is 3 .03 g and each dime is 2 .29 g . Each piece of candy weighs 10.23 g . Using this data the following calculations have to be done – (a) Number of pennies you have (b) Number of dimes you need to buy as many candies as possible (c) Weight of all the dimes (d) Number of candy pieces you could buy (e) The weight of the total number of candies that u bought as described above.
Given that three pennies and two dimes are equivalent to
$0.23. You have
636.3 g of pennies and each penny is
3.03 g and each dime is
2.29 g. Each piece of candy weighs
10.23 g. Using this data the following calculations have to be done –
(a) Number of pennies you have
(b) Number of dimes you need to buy as many candies as possible
(c) Weight of all the dimes
(d) Number of candy pieces you could buy
(e) The weight of the total number of candies that u bought as described above.
(b)
Interpretation Introduction
Interpretation:
Given that three pennies and two dimes are equivalent to
$0.23. You have
636.3 g of pennies and each penny is
3.03 g and each dime is
2.29 g. Each piece of candy weighs
10.23 g. Using this data the following calculations have to be done –
(a) Number of pennies you have
(b) Number of dimes you need to buy as many candies as possible
(c) Weight of all the dimes
(d) Number of candy pieces you could buy
(e) The weight of the total number of candies that u bought as described above.
(c)
Interpretation Introduction
Interpretation:
Given that three pennies and two dimes are equivalent to
$0.23. You have
636.3 g of pennies and each penny is
3.03 g and each dime is
2.29 g. Each piece of candy weighs
10.23 g. Using this data the following calculations have to be done –
(a) Number of pennies you have
(b) Number of dimes you need to buy as many candies as possible
(c) Weight of all the dimes
(d) Number of candy pieces you could buy
(e) The weight of the total number of candies that u bought as described above.
(d)
Interpretation Introduction
Interpretation:
Given that three pennies and two dimes are equivalent to
$0.23. You have
636.3 g of pennies and each penny is
3.03 g and each dime is
2.29 g. Each piece of candy weighs
10.23 g. Using this data the following calculations have to be done –
(a) Number of pennies you have
(b) Number of dimes you need to buy as many candies as possible
(c) Weight of all the dimes
(d) Number of candy pieces you could buy
(e) The weight of the total number of candies that u bought as described above.
(e)
Interpretation Introduction
Interpretation:
Given that three pennies and two dimes are equivalent to
$0.23. You have
636.3 g of pennies and each penny is
3.03 g and each dime is
2.29 g. Each piece of candy weighs
10.23 g. Using this data the following calculations have to be done –
(a) Number of pennies you have
(b) Number of dimes you need to buy as many candies as possible
(c) Weight of all the dimes
(d) Number of candy pieces you could buy
(e) The weight of the total number of candies that u bought as described above.
b) Certain cyclic compounds are known to be conformationally similar to carbohydrates, although they are not
themselves carbohydrates. One example is Compound C shown below, which could be imagined as adopting
four possible conformations. In reality, however, only one of these is particularly stable. Circle the conformation
you expect to be the most stable, and provide an explanation to justify your choice. For your explanation to be
both convincing and correct, it must contain not only words, but also "cartoon" orbital drawings contrasting the
four structures.
Compound C
Possible conformations (circle one):
Дет
Lab Data
The distance entered is out of the expected range.
Check your calculations and conversion factors.
Verify your distance. Will the gas cloud be closer to the cotton ball with HCI or NH3?
Did you report your data to the correct number of significant figures?
- X
Experimental Set-up
HCI-NH3
NH3-HCI
Longer Tube
Time elapsed (min)
5 (exact)
5 (exact)
Distance between cotton balls (cm)
24.30
24.40
Distance to cloud (cm)
9.70
14.16
Distance traveled by HCI (cm)
9.70
9.80
Distance traveled by NH3 (cm)
14.60
14.50
Diffusion rate of HCI (cm/hr)
116
118
Diffusion rate of NH3 (cm/hr)
175.2
175.2
How to measure distance and calculate rate
For the titration of a divalent metal ion (M2+) with EDTA, the stoichiometry of the reaction is typically:
1:1 (one mole of EDTA per mole of metal ion)
2:1 (two moles of EDTA per mole of metal ion)
1:2 (one mole of EDTA per two moles of metal ion)
None of the above
Chapter 1 Solutions
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell