Concept explainers
To find: The interval in which the function increases, using graphing utility.
The required intervals is (1,∞) .
Given data: The given function is y=2+|x−1| .
Method/Formula used:
An interval (a,b) or [a,b],or[a,b) or(a,b] of the domain of function f(x) is said to be interval of increasing, if for two numbers x1,x2∈(a,b) or [a,b],or[a,b) or(a,b] , f(x1)<f(x2) , when x1<x2 .
Calculation:
Let y=2+|x−1| or f(x)=2+|x−1| .
The graph of the function f(x)=2+|x−1| is shown in Fig. (1).
From the graph, the point (1,2) divides the graph into two segments.
Consider two values of x , x1,x2∈(1,∞) such that x1<x2 , say x1=2,x2=3 , then f(x1=2)=2+|2−1|=2+1=3
And
f(x1=3)=2+|3−1|=2+2=4
This shows that for x1(=2)<x2(=3)∈(0,∞) , f(x1)=3<f(x2)=4 , therefore, the function f(x)=x3/6 is increasing in the interval (1,∞) .
Consider two values of x , x1,x2∈(−∞,1) such that x1<x2 , say x1=−2,x2=−1 , then f(x1=−2)=2+|−2−1|=2+3=5
And
f(x1=−1)=2+|−1−1|=2+2=4
−2<−1⇒{f(−2)=5}>{f(−1)=4}
This shows that for x1<x2∈(0,∞) , f(x1)>f(x2) , therefore, the function f(x)=2+|x−1| is decreasing in the interval x1,x2∈(−∞,1) .
Thus, the function f(x)=2+|x−1| is increasing in the interval (1,∞) .
Chapter 1 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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