The energy of a sodium atom when it generates a photon of wavelength 589 n m has to be calculated. Concept Introduction: Energy of a photon can be expressed mathematically as given below. E = h ν = h c λ Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

Question

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Answer 1

Question

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

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Answer 2

Question

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

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Answer 3

Question

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

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Answer 4

Question

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

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Answer 5

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Answer 6

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Answer 7

Chapter 1, Problem 1B.7E

(a)

Interpretation Introduction

Interpretation:

The energy of a sodium atom when it generates a photon of wavelength 589 nm has to be calculated.

Concept Introduction:

Energy of a photon can be expressed mathematically as given below.

E=hν=hcλ

Where, h is the Planck’s constant, ν is the frequency of radiation, c is the speed of light and λ is the wavelength of the radiation.

Answer 8

(a)

Expert Solution

Answer to Problem 1B.7E

The energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given that, the wavelength is 589 nm. The corresponding energy of a sodium atom when it generates a photon can be calculated as given below.

E=hν=hcλE=(6.626×10−34J.s)×(3×108m/s)589×10−9mE=3.37×10-19J[∵ 1 nm=10−9m]

Therefore, the energy of a sodium atom when it generates a photon of wavelength 589 nm is 3.37×10-19J.

Answer 13

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Answer 14

(b)

Interpretation Introduction

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

Answer 15

(b)

Expert Solution

Answer to Problem 1B.7E

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation of number of sodium atoms present in 5.00 mg of sodium atoms:

1 mole of Na=23.0 g1 g=1000 mg1 mole of Na contains 6.022×1023atoms.So, 5.00mg×1 g1000 mg×1 mole23.0 g×6.022×1023atoms1 mole=1.31×1020atoms

The energy of one sodium atom is 3.37×10-19J. Then the energy of 1.31×1020atoms of sodium can be calculated as given below.

E=(1.31×1020)×(3.37×10−19J)=44.1 J

Therefore, the energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm is 44.1 J.

Answer 20

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Answer 21

(c)

Interpretation Introduction

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

Answer 22

(c)

Expert Solution

Answer to Problem 1B.7E

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The energy of one sodium atom is 3.37×10-19J.

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm can be calculated as shown below.

E(per mole of photons)=NAE(1 photon)E(per mole of photons)=(6.022×1023mol−1)×(3.37×10-19J)E(per mole of photons)=2.03×105J.mol-1

Therefore, the energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm is 2.03×105J.mol-1.

Answer 27

Ch. 1 - Prob. 1A.1AST Ch. 1 - Prob. 1A.1BST Ch. 1 - Prob. 1A.2AST Ch. 1 - Prob. 1A.2BST Ch. 1 - Prob. 1A.1E Ch. 1 - Prob. 1A.3E Ch. 1 - Prob. 1A.4E Ch. 1 - Prob. 1A.5E Ch. 1 - Prob. 1A.6E Ch. 1 - Prob. 1A.7E

Concept explainers

Videos

Answer to Problem 1B.7E

Explanation of Solution

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

Answer to Problem 1B.7E

Explanation of Solution

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

Answer to Problem 1B.7E

Explanation of Solution

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Chapter 1 Solutions

Concept explainers

Videos

Answer to Problem 1B.7E

Explanation of Solution

Interpretation: The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated. Concept Introduction: Refer to part (a).

Answer to Problem 1B.7E

Explanation of Solution

Interpretation: The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated. Concept Introduction: Refer to part (a).

Answer to Problem 1B.7E

Explanation of Solution

Want to see more full solutions like this?

Chapter 1 Solutions

Interpretation:

The energy of 5.00 mg sodium atoms emitting light at wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).

Interpretation:

The energy of 1.00 mole sodium atoms emitting light of wavelength 589 nm has to be calculated.

Concept Introduction:

Refer to part (a).