Chapter 1, Problem 1B.3BST

(a)

Interpretation Introduction

Interpretation:

The kinetic energy of the ejected electron having a speed of $785km.s^{-1}$ has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, $E_k=\frac{1}{2}{m}_e{v}^2.$  An equation which represents the kinetic energy is given below.

  $E_k=h\nu -\Phi$

Where, $E_k$ is the kinetic energy, $h$ is the Planck’s constant, $\nu$ is the frequency of radiation and $\Phi$ is the work function.

(b)

Interpretation Introduction

Interpretation:

The wavelength of the radiation that caused photoejection of the electron has to be calculated.

Concept Introduction:

Refer to part (a).