Chapter 1, Problem 1.70AP

Carry out each of the following conversions.

1. a. 25 μL to mL
2. b. 35 kg to g
3. c. 300 mL to qt
4. d. 3 cups to L

Interpretation Introduction

Interpretation:

The value $\text{25 μL}$ has to be converted into milliliter $\left(\text{mL}\right)\text{.}$

Answer to Problem 1.70AP

The conversion of $\text{25 μL}$ into milliliter is $\text{2}{\text{.5×10}}^{\text{-2}}\text{mL}\text{.}$

Explanation of Solution

The given value is $\text{25 μL}\text{.}$

Microliters can be converted into Liters using the conversion factor,

  $\frac{\text{1}\text{L}}{{\text{10}}^{\text{6}}\text{μL}}$

Liters can be converted to milliliters using the conversion factor,

  $\frac{\text{1000}\text{mL}}{\text{1}\text{L}}$

The value in milliliters is obtained as,

  $\begin{array}{l}\text{mL=25}\cancel{\text{μL}}\text{×}\frac{\text{1}\cancel{\text{L}}}{{\text{10}}^{\text{6}}\cancel{\text{μL}}}\text{×}\frac{\text{1000}\text{mL}}{\text{1}\cancel{\text{L}}}\\ \text{mL=2}{\text{.5×10}}^{\text{-2}}\text{mL}\end{array}$

The conversion of $\text{25 μL}$ into milliliter is $\text{2}{\text{.5×10}}^{\text{-2}}\text{mL}\text{.}$

Interpretation Introduction

Interpretation:

The value $\text{35}\text{kg}$ has to be converted into grams $\left(\text{g}\right)\text{.}$

Answer to Problem 1.70AP

The conversion of $\text{35}\text{kg}$ into grams is $\text{3}{\text{.5×10}}^{\text{4}}\text{g}\text{.}$

Explanation of Solution

The given value is $\text{35}\text{kg}\text{.}$

Kilograms is converted into grams as,

  $\frac{\text{1000}\text{g}}{\text{1}\text{kg}}$

The value in grams is obtained as,

  $\begin{array}{l}\text{g=35}\cancel{\text{kg}}\text{×}\frac{\text{1000}\text{g}}{\text{1}\cancel{\text{kg}}}\\ \text{g=3}{\text{.5×10}}^{\text{4}}\text{g}\end{array}$

The conversion of $\text{35}\text{kg}$ into grams is $\text{3}{\text{.5×10}}^{\text{4}}\text{g}\text{.}$

Interpretation Introduction

Interpretation:

The value $\text{300}\text{mL}$ has to be converted into quart $\left(\text{qt}\right)\text{.}$

Answer to Problem 1.70AP

The conversion of $\text{300}\text{mL}$ into quart is $\text{0}\text{.3}\text{qt}\text{.}$

Explanation of Solution

The given value is $\text{300}\text{mL}\text{.}$

Milliliter can be converted into quart using conversion factor,

  $\frac{\text{1 qt}}{\text{946}\text{mL}}$

The value in quart is obtained as,

  $\begin{array}{l}\text{qt=300}\cancel{\text{mL}}\text{×}\frac{\text{1}\text{qt}}{\text{946}\cancel{\text{mL}}}\\ \text{qt=0}\text{.3171}\text{qt}\end{array}$

The original measurement has one significant figure, on rounding off, the value in quart is $\text{0}\text{.3}\text{qt}\text{.}$

The conversion of $\text{300}\text{mL}$ into quart is $\text{0}\text{.3}\text{qt}\text{.}$

Interpretation Introduction

Interpretation:

The value $\text{3}\text{cups}$ has to be converted into liters $\left(\text{L}\right)\text{.}$

Answer to Problem 1.70AP

The conversion of $\text{3}\text{cups}$ into Liters is $\text{0}\text{.7 L}\text{.}$

Explanation of Solution

The given value is $\text{3}\text{cups}\text{.}$

Cups in converted to quart $\left(\text{qt}\right)$ using the conversion factor,

  $\frac{\text{1}\text{qt}}{\text{4}\text{cups}}$

Quart $\left(\text{qt}\right)$ is converted into liters using the conversion factor,

  $\frac{\text{1}\text{L}}{\text{1}\text{.06}\text{qt}}$

The value in liters is calculated as,

  $\begin{array}{l}\text{L=3}\cancel{\text{cups}}\text{×}\frac{\text{1}\cancel{\text{qt}}}{\text{4}\cancel{\text{cups}}}\text{×}\frac{\text{1}\text{L}}{\text{1}\text{.06}\cancel{\text{qt}}}\\ \text{L=0}\text{.7075}\text{L}\end{array}$

The original measurement has one significant figure, on rounding off, the value in meters is $\text{0}\text{.7 L}\text{.}$

The conversion of $\text{3}\text{cups}$ into Liters is $\text{0}\text{.7 L}\text{.}$