Chapter 1, Problem 1.84AP

(a)

Interpretation Introduction

Interpretation:

The specific gravity of mercury from the density of mercury $\text{13}\text{.6 g/mL}$ has to be calculated.

Concept Introduction:

Specific gravity:  The quantity that compares the density of a substance with the density of water at ${\text{4}}^{\text{o}}\text{C}$ is called as specific gravity.  The specific gravity of a substance equals its density, but does not contain any units.

The formula to calculate specific gravity is,

  $\text{Specific}\text{gravity=}\frac{\text{Density}\text{of}\text{a}\text{substance}\left(\text{g/mL}\right)}{\text{Density}\text{of}\text{water}\left(\text{g/mL}\right)}$

(b)

Interpretation Introduction

Interpretation:

The density of ethanol, whose specific gravity is $\text{0}\text{.789}$ has to be calculated.

Concept Introduction:

Refer to part (a).