Concept explainers
(a)
Interpretation:
The answers of the given divisions are to be expressed by using scientific notation.
Concept introduction:
Scientific notation is used to write large numbers or small numbers as the product of a nonexponential term and exponential term in the form of
Answer to Problem 1.59E
The answers of the given divisions expressed by using scientific notation is
Explanation of Solution
The given question is,
On division the answer obtained is
The above answer is adjusted to a standard position. The decimal is shifted two places to the left and the power of
The answers of the given divisions expressed by using scientific notation is
(b)
Interpretation:
The answers of the given divisions are to be expressed by using scientific notation.
Concept introduction:
Scientific notation is used to write large numbers or small numbers as the product of a nonexponential term and exponential term in the form of
Answer to Problem 1.59E
The answers of the given divisions expressed by using scientific notation is
Explanation of Solution
The given question is,
The fraction can be expressed as follows:
The answer of a given fraction can be calculated as follows:
Hence, the answer of a given division is
The answers of the given divisions expressed by using scientific notation is
(c)
Interpretation:
The answers of the given divisions are to be expressed by using scientific notation.
Concept introduction:
Scientific notation is used to write large numbers or small numbers as the product of a nonexponential term and exponential term in the form of
Answer to Problem 1.59E
The answers of the given divisions expressed by using scientific notation is
Explanation of Solution
The given question is,
The fraction can be expressed as follows:
The answer of a given fraction can be calculated as follows:
Hence, the answer of a given division is
The answers of the given divisions expressed by using scientific notation is
(d)
Interpretation:
The answers of the given divisions are to be expressed by using scientific notation.
Concept introduction:
Scientific notation is used to write large numbers or small numbers as the product of a nonexponential term and exponential term in the form of
Answer to Problem 1.59E
The answers of the given divisions expressed by using scientific notation is
Explanation of Solution
The given question is,
The fraction can be expressed as follows:
The answer of a given fraction can be calculated as follows:
Hence, the answer of a given division is
The answers of the given divisions expressed by using scientific notation is
(e)
Interpretation:
The answers of the given divisions are to be expressed by using scientific notation.
Concept introduction:
Scientific notation is used to write large numbers or small numbers as the product of a nonexponential term and exponential term in the form of
Answer to Problem 1.59E
The answers of the given divisions expressed by using scientific notation is
Explanation of Solution
The given question is,
The fraction can be expressed as follows:
The answer of a given fraction can be calculated as follows:
The above answer is adjusted to a standard position. The decimal is shifted towards one place right and the power of
The answers of the given divisions expressed by using scientific notation is
Want to see more full solutions like this?
Chapter 1 Solutions
Chemistry for Today: General, Organic, and Biochemistry
- 1.47 A student weighs 10 quarters and finds that their total mass is 56.63 grams. What should she report as the average mass of quarter based on her data?arrow_forwardCarry out the indicated temperature conversions. 153 °F to kelvins 153 °C to kelvins 555 °C to Fahrenheit degrees 24 °F to Celsius degreesarrow_forwardConsider multiplying “26.2” by “16.43.” What would a mathematician say the answer is? What would a scientist say? Justify the scientist’s answer, not merely citing the rule, hut explaining it.arrow_forward
- Given that the volume of a rectangular object is computed is given by the formula V = l × w × h, what is the volume of a block of metal that is 20 inches long, 1.2 feet wide, and 3.4 feet tall? Select one: a. 8.61 ft b. 0.204 cm c. 1.9×103 cm d. 2.1×105 cm3arrow_forwardUse scientific notation to express each quantity with only base units (no prefix multipliers).a. 4.5 ns b. 18 fs c. 128 pm d. 35 mmarrow_forwardCarry out the following multiplications and divisions, expressing your answer in scientific notation to the a correct number of significant figures.a. (3.20 × 107) × (1.720 × 105) b. (1.00 × 103) × (5.00 × 103) × (3.0 × 10−3) c. 3.0 3 10251.5 3 102d. 12.2 3 106 2 3 12.3 3 1026 211.2 3 1023 2 3 13.5 3 1023 2arrow_forward
- Conversions: include the correct number of significant digits and follow the format included in the image. a. 0.20 m to mm b. 2.23 ks to s c. 78.9 mg to garrow_forwardA backyard swimming pool holds a volume of 190 cubic yards (yd3) of water. How many of the following dimensions are equivalent to 190 yd3 ? Assume the density of water is 1.00 g/mL A. 4.77 x 105 mL B. 1.45 x 105 kg C. 1.74 x 102 m3 D. 1.45 x 108 cm3 E. 1.74 x 105 cm3arrow_forwardConvert 8.900 x 10–8 meters to nanometers and express the answer in standard notation using the correct number of significant figures. The choices are: A. 89.0 nm B. 0.8900 C. 8.90 nm D. 89.00 nm E. 89 nmarrow_forward
- Conversions involving units raised to a power: include the correct number of significant digits. a. 5.00 mm^3 to cm^3 b. 75 acres to m^2 c. 4637 nm^3 to in^3arrow_forwardIt is known that the density of mercury is 13.54 times the density of water. What volume of this mercury in liters would weigh the same as 0.020m^3 of fuel oil, when the fuel oil weighs 9.42kN for every cubic meter? a. 71 b. 1.42 c. 1.7 d. 2.4arrow_forwardIf Michael Jordan is 6 feet and 7 inches. What is his height in meters if 1 ft = 12 in, 1m-D3.28 %3D ft? * O a. 2.0065 O b. 2.0066 O c. 2.0067 O d. 2.0068arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning