Explanation Given: Temperature of air is 20 ° C , thermal conductivity of normal plate is 0.05 W/mk , thermal conductivity of stainless steel is 15 W/mk , thickness of the plate is 38 mm , uniform flux at the bottom side is 200 W/m 2 , maximum temperature of steel plate is 260 ° C , maximum temperature of bolt is 149 ° C , surrounding surface temperature is 30 ° C , convection heat transfer coefficient is 5 W/m 2 k and emissivityis 0.3 . Concept used: Expression heat transfer in convection mode is given as follows: Q c = h A ( T 2 − T ∞ ) …… (1) Here, convection coefficient is h , exposed surface area is A , heat transfer through convection is Q c , surface temperature of normal plate is T 2 and ambient temperature is T ∞ . Expression heat transfer in radiation mode is given as follows: Q r = ε σ A ( T 2 4 − T s u r 4 ) …… (2) Here, Stefan-Boltzmann constant is σ , exposed surface area is A , heat transfer through radiation is Q r , surface temperature of normal plate is T 2 and surrounding temperature is T s u r . Expression for conduction heat transfer through plate is given as follows: q = − k d T d t …… (3) Here, heat flux is q and thermal conductivity is k . Calculation: For steady heat transfer in plates, the heat balance from equations (1) and (2) are given as follows: Q A = ε σ ( T 2 4 − T s u r 4 ) + h ( T 2 − T ∞ ) 200 = 0

6th Edition

ISBN: 9781265879631

Author: CENGEL

Publisher: MCG CUSTOM

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Chapter 1, Problem 106P

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Compilation of both ASME codes under given conditions.

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Chapter 1, Problem 105P

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HEAT+MASS TRANSFER (LL)-W/ACCESS

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