It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as WCTI ( ∘ C ) = 13.12 + 0.6215 T − 11.37 V 0.16 + 0.3965 T V 0.16 Where T is the air temperature in ∘ C and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as WCTI ( ∘ F ) = 35.74 + 0.6215 T − 35.75 V 0.16 + 0.4275 T V 0.16 Where T is the air temperature in ∘ F and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to − 60 ∘ C and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as WCTI ( ∘ C ) = 13.12 + 0.6215 T − 11.37 V 0.16 + 0.3965 T V 0.16 Where T is the air temperature in ∘ C and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as WCTI ( ∘ F ) = 35.74 + 0.6215 T − 35.75 V 0.16 + 0.4275 T V 0.16 Where T is the air temperature in ∘ F and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to − 60 ∘ C and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
Solution Summary: The author explains the relation in English unit as WCTI(°F) = 35.74+0.6215T35.75V0.16+0.4275TV0.16, and calculates the change of metric unit to
It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as
WCTI
(
∘
C
)
=
13.12
+
0.6215
T
−
11.37
V
0.16
+
0.3965
T
V
0.16
Where T is the air temperature in
∘
C
and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as
WCTI
(
∘
F
)
=
35.74
+
0.6215
T
−
35.75
V
0.16
+
0.4275
T
V
0.16
Where T is the air temperature in
∘
F
and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to
−
60
∘
C
and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
500
Q3: The attachment shown in Fig.3 is made of
1040 HR. The static force is 30 kN. Specify the
weldment (give the pattern, electrode
number, type of weld, length of weld, and leg
size).
Fig. 3
All dimension
in mm
30 kN
100
(10 Marks)
(read image) (answer given)
A cylinder and a disk are used as pulleys, as shown in the figure. Using the data
given in the figure, if a body of mass m = 3 kg is released from rest after falling a
height h 1.5 m, find:
a) The velocity of the body.
b) The angular velocity of the disk.
c) The number of revolutions the cylinder has made.
T₁
F
Rd =
0.2 m
md =
2 kg
T
T₂1
Rc = 0.4 m
mc = 5 kg
☐ m = 3 kg
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