How does the science of heat transfer differ from the science of thermodynamics?
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Expert Solution & Answer
To determine
The difference between science of heat transfer and science of thermodynamics.
Explanation of Solution
Heat transfer is defined as the science which deals with the rate of transfer of energy. It tells about the basic information of the amount of heat transfer at a specified instantaneous time. Transfer of heat occurs when there is difference in the temperature of the body and the surroundings. It does not achieve equilibrium stage as heat transfer is a non-equilibrium phenomenon.
Whereas,the science of thermodynamics deals with the amount of heat transfer when a system experiences state change. It does not give any information about the rate of energy transfer.
Thermodynamics system does not give any information related to the nature of the state change.Heat transfer takes place from the region of higher temperature to the region of low temperature.
Fig.-1: Modes of heat transfer.
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Calculate the vertical cross section moment of inertia for Orientations 1 and 2. State which number is the higher moment of inertia using equation 1. Given: b1=1 in, h1=1.5 in, b2=1.5 in, h2=1 in, t=0.0625 in. Then calculate the maximum deflection for a point load of 8 lb on the free end of the beam using equation 2. Given: E=10.1*10^6 psi.
1. ((bh^3)/12) - (((b-2t)(h-2t)^3))/12)
2. S = (PL^3)/(3EI)
1-69E The pressure in a natural gas pipeline is measured by the manometer shown in Fig. P1-69E with one of the arms open to the
atmosphere where the local atmospheric pressure is 14.2 psia. Determine the absolute pressure in the pipeline.
Natural
Gas
10 in
6 in
FIGURE P1-69E
Mercury
SG= 13.6
Air
2 in
+
25 in
Water
B
150 mm
120 mm
PROBLEM 15.193
The L-shaped arm BCD rotates about the z axis with a constant
angular velocity @₁ of 5 rad/s. Knowing that the 150-mm-
radius disk rotates about BC with a constant angular velocity
@2 of 4 rad/s, determine (a) the velocity of Point A, (b) the
acceleration of Point A.
Answers:
V₁ =-(0.600 m/s)i + (0.750 m/s)j - (0.600 m/s)k
a=-(6.15 m/s²)i- (3.00 m/s²)j
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