Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 0.2, Problem 18E

a)

To determine

the expressions for the Monica’s new office.

a)

Expert Solution
Check Mark

Answer to Problem 18E

Expressions for dimensions of Monica’s new office is (x+3) and (x+5) .

Explanation of Solution

Given information:

It is given that Monica’s current office is in the shape of square. Her office in the company’s new building will be 3feet wider and 5 feet longer.

Let the length of the side of current office be x.

According to the question, her new office, will have

Length = (x+3)

Breadth = (x+5)

So,

Expressions for dimensions of Monica’s new office is (x+3) and (x+5) .

b)

To determine

the polynomial expression for the area of Monica’s new office.

b)

Expert Solution
Check Mark

Answer to Problem 18E

The expression after product of the length and breadth is x2+8x+15 .

Explanation of Solution

Given information:

It is given that Monica’s current office is in the shape of square. Her office in the company’s new building will be 3feet wider and 5 feet longer.

According to the question, her new office, will have

Length = (x+3)

Breadth = (x+5)

So,

Expressions for polynomial expression for the area of Monica’s new office = (x+3)(x+5) .

After simplifying it,

  (x+3)(x+5)=x(x+5)+3(x+5)=x2+5x+3x+15=x2+8x+15

c)

To determine

the value by how much it is large than previous office.

c)

Expert Solution
Check Mark

Answer to Problem 18E

The new office is 71 feet2is larger.

Explanation of Solution

Given information:

It is given that Monica’s current office is in the shape of square. Her office in the company’s new building will be 3feet wider and 5 feet longer.

According to the question, her new office, will have

Length = (x+3)

Breadth = (x+5)

So,

Expressions for polynomial expression for the area of Monica’s new office = (x+3)(x+5) .

After simplifying it,

  (x+3)(x+5)=x(x+5)+3(x+5)=x2+5x+3x+15=x2+8x+15

Here, it is being asked to suppose Monica’s current office is 7 feet by 7 feet.

The area of current office is 49feet2.

Now, finding the area of the Monica’s new office,

By putting x = 7,

  (x+3)(x+5)=(7+3)(7+5)=10×12=120feet2

So,

Difference in area =

  12049=71feet2

So, the new office is 71 feet2is larger.

Chapter 0 Solutions

Algebra 2

Ch. 0.1 - Prob. 11ECh. 0.1 - Prob. 12ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.3 - Prob. 24ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.4 - Prob. 8ECh. 0.4 - Prob. 9ECh. 0.4 - Prob. 10ECh. 0.4 - Prob. 11ECh. 0.4 - Prob. 12ECh. 0.4 - Prob. 13ECh. 0.4 - Prob. 14ECh. 0.4 - Prob. 15ECh. 0.4 - Prob. 16ECh. 0.5 - Prob. 1ECh. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.5 - Prob. 11ECh. 0.5 - Prob. 12ECh. 0.5 - Prob. 13ECh. 0.5 - Prob. 14ECh. 0.5 - Prob. 15ECh. 0.5 - Prob. 16ECh. 0.5 - Prob. 17ECh. 0.5 - Prob. 18ECh. 0.5 - Prob. 19ECh. 0.5 - Prob. 20ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Prob. 11ECh. 0.6 - Prob. 12ECh. 0.7 - Prob. 1ECh. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0.7 - Prob. 10ECh. 0.7 - Prob. 11ECh. 0.7 - Prob. 12ECh. 0.7 - Prob. 13ECh. 0.7 - Prob. 14ECh. 0.7 - Prob. 15ECh. 0.7 - Prob. 16ECh. 0.7 - Prob. 17ECh. 0 - Prob. 1PRCh. 0 - Prob. 2PRCh. 0 - Prob. 3PRCh. 0 - Prob. 4PRCh. 0 - Prob. 5PRCh. 0 - Prob. 6PRCh. 0 - Prob. 7PRCh. 0 - Prob. 8PRCh. 0 - Prob. 9PRCh. 0 - Prob. 10PRCh. 0 - Prob. 11PRCh. 0 - Prob. 12PRCh. 0 - Prob. 13PRCh. 0 - Prob. 14PRCh. 0 - Prob. 15PRCh. 0 - Prob. 16PRCh. 0 - Prob. 17PRCh. 0 - Prob. 18PRCh. 0 - Prob. 19PRCh. 0 - Prob. 20PRCh. 0 - Prob. 21PRCh. 0 - Prob. 22PRCh. 0 - Prob. 23PRCh. 0 - Prob. 24PRCh. 0 - Prob. 25PRCh. 0 - Prob. 26PRCh. 0 - Prob. 27PRCh. 0 - Prob. 28PRCh. 0 - Prob. 29PRCh. 0 - Prob. 30PRCh. 0 - Prob. 31PRCh. 0 - Prob. 32PRCh. 0 - Prob. 33PRCh. 0 - Prob. 34PRCh. 0 - Prob. 1POCh. 0 - Prob. 2POCh. 0 - Prob. 3POCh. 0 - Prob. 4POCh. 0 - Prob. 5POCh. 0 - Prob. 6POCh. 0 - Prob. 7POCh. 0 - Prob. 8POCh. 0 - Prob. 9POCh. 0 - Prob. 10POCh. 0 - Prob. 11POCh. 0 - Prob. 12POCh. 0 - Prob. 13POCh. 0 - Prob. 14POCh. 0 - Prob. 15POCh. 0 - Prob. 16POCh. 0 - Prob. 17POCh. 0 - Prob. 18POCh. 0 - Prob. 19POCh. 0 - Prob. 20POCh. 0 - Prob. 21POCh. 0 - Prob. 22POCh. 0 - Prob. 23POCh. 0 - Prob. 24POCh. 0 - Prob. 25POCh. 0 - Prob. 26POCh. 0 - Prob. 27POCh. 0 - Prob. 28POCh. 0 - Prob. 29POCh. 0 - Prob. 30POCh. 0 - Prob. 31POCh. 0 - Prob. 32POCh. 0 - Prob. 33POCh. 0 - Prob. 34PO
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