Chapter 0.2, Problem 12E

To determine

the product.

Answer to Problem 12E

  $\left(7n-2\right)\left(n+3\right)=7n^2+19n-6$

Explanation of Solution

Given information:

  $\left(7n-2\right)\left(n+3\right)$

It is given that $\left(7n-2\right)\left(n+3\right)$

So,

  $\begin{array}{c}\left(7n-2\right)\left(n+3\right)=7n\left(n+3\right)-2\left(n+3\right)\\ 7n\left(n+3\right)-2\left(n+3\right)=7n^2+21n-2n-6\\ 7n^2+21n-2n-6=7n^2+19n-6\end{array}$

So,

  $\left(7n-2\right)\left(n+3\right)=7n^2+19n-6$