Chapter 0.2, Problem 7E

To determine

the product.

Answer to Problem 7E

  $\left(r+3\right)\left(r-8\right)=r^2-5r-24$

Explanation of Solution

Given information:

  $\left(r+3\right)\left(r-8\right)$

It is given that $\left(r+3\right)\left(r-8\right)$

So,

  $\begin{array}{c}\left(r+3\right)\left(r-8\right)=r\left(r-8\right)+3\left(r-8\right)\\ r\left(r-8\right)+3\left(r-8\right)=r^2-8r+3r-24\\ r^2-8r+3r-24=r^2-5r-24\end{array}$

So,

  $\left(r+3\right)\left(r-8\right)=r^2-5r-24$