Chapter 0.3, Problem 17E

To determine

To evaluate: the factors of polynomial.

Answer to Problem 17E

The factor of polynomial $9x^2-24x+16$ is $\left(3x-4\right)\left(3x-4\right)$ .

Explanation of Solution

Given information:

Polynomial is given as $9x^2-24x+16$

Factorizing the given polynomial,

  $\begin{array}{c}9x^2-24x+16=9x^2-12x-12x+16\\ 9x^2-12x-12x+16=3x\left(3x-4\right)-4\left(3x-4\right)\\ 3x\left(3x-4\right)-4\left(3x-4\right)=\left(3x-4\right)\left(3x-4\right)\end{array}$

So,

After factorizing $\left(3x-4\right)\left(3x-4\right)$ .