Chapter 0, Problem 42PR

To determine

The circumference and area of the given circle.

Answer to Problem 42PR

  $\begin{array}{l}A=201{\text{ cm}}^2\\ C=50.2\text{ cm}\end{array}$

Explanation of Solution

Given:

Diameter $d=16$ cm

Radius $r=\frac{d}{2}=8$ cm

Formula used:

Area of circle,

  $A=\pi r^2$

Circumference of circle,

  $C=2\pi r$

Where,

  $r=$ Radius

Calculation:

Area of circle,

  $\begin{array}{l}A=\pi r^2\\ A=3.14\times {\left(8\right)}^2\\ A=200.96{\text{ cm}}^2\end{array}$

Nearest tenth is 201, so the area of circle is ${\text{201 cm}}^2$ .

Circumference of circle,

  $\begin{array}{l}C=2\pi r\\ C=2\times 3.14\times 8\\ C=50.24\text{ m}\end{array}$

Nearest tenth is 50.2, so the circumference of circle is $\text{50}\text{.2 cm}$ .

Conclusion:

Hence, the circumference of circle is $\text{50}\text{.2 cm}$ .and area of circle is ${\text{201 cm}}^2$ .