Chapter 0.8, Problem 4E

To determine

To calculate: The area of the triangle with base 12 millimeters and height 11 millimeters.

Answer to Problem 4E

The area of the triangle is ${\text{66 mm}}^{\text{2}}$ .

Explanation of Solution

Given information:

A triangle with base 12 millimeters and height 11 millimeters.

Formula used:

Area $\left(A\right)$ of triangle is half into product of its height and base. Let the base be $\left(b\right)$ and the height be $\left(h\right)$ then it is mathematically denoted by $A=\frac{1}{2}\cdot b\cdot h$ .

Calculation:

Consider the provided statement a triangle with base 12 millimeters and height 11 millimeters.

Recall that area $\left(A\right)$ of triangle is half into product of its height and base. Let the base be $\left(b\right)$ and the height be $\left(h\right)$ then it is mathematically denoted by $A=\frac{1}{2}\cdot b\cdot h$ .

Apply it,

  $\begin{array}{c}A=\frac{1}{2}\cdot b\cdot h\\ =\frac{1}{2}\cdot 12\cdot 11\\ =66{\text{mm}}^{\text{2}}\end{array}$

Thus, the area of the triangle is ${\text{66 mm}}^{\text{2}}$ .