Zinc-air batteries are actively being researched because one reactant (oxygen) is provided ininfinite supply for free. The standard cell potential for this battery is 1.65 V. If the cell potentialis 1.61 V, what is the partial pressure of oxygen in the cell and a temperature is 25.0\deg C? Thereaction in the cell converts Zn(s) and O2(g) into ZnO(s).2Zn(s) 02 (g) -> 2ZnO(s)

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Answered: Zinc-air batteries are actively being…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Similar questions

Consider the following reaction at 298K. Fe2+ (aq) + Sn (s) — Fe (s) + Sn²+ (aq) Which of the following statements are correct? Choose all that apply. ☐ delta G° <0 Eº cell <0 K< 1 The reaction is product-favored. ☐ n = 1 mol electrons
The reaction below occurs in nearly all human cells. It is catalyzed by the enzyme enolase. CO- CO- enolase -OPO3 OPO3 + H20 ČH,OH AGO'=+1.7 kJ/mol CH2 2PGA PEP Under cellular conditions, the AG is -3.3 kJ/mol. Which of the following could account for these changes in cellular AG compared to the standard biological free energy? The concentration of 2PGA is 7 times higher than PEP. The concentration of PEP is 7 times higher than 2PGA Enolase lowers the activation energy of the transition state. The release of water from 2PGA is a form of energy coupling.
1. a. Calculate the physiological DG of the reaction shown below at 37°C, as it occurs in the cytosol ofneurons, with phosphocreatine at 4.7 mM, creatine at 1.0 mM, ADP at 0.73 mM, and ATP at 2.6mM. The standard free energy change for the overall reaction is –12.5 kJ/mol. Phosphocreatine + ADP ® creatine + ATP b. The enzyme phosphoglucomutase catalyzes the conversion of glucose 1-phosphate to glucose6-phosphate. Calculate the standard free energy change of this reaction if incubation of 20 mMglucose 1-phosphate (no glucose-6 phosphate initially present) yields a final equilibrium mixtureof 1.0 mM glucose 1-phosphate and 19 mM glucose 6-phosphate at 25°C and pH 7.0. c. If the rate of a nonenzymatic reaction is 1.2 x 10–2 μM s–1, what is the rate of the reaction at 37℃ inthe presence of an enzyme that reduces the activation energy by 30.5 kJ/mol?
A particular reaction has a ΔG‡ of 37.0 kJ mol-1. In the presence of an enzyme, the same reaction has a ΔG‡ of 5.70 kJ mol-1. Calculate the value of ΔΔG‡ in kJ mol-1.
Consider the following reaction and its equilibrium constant: 12(g) 21(g) Kp = 0.209 atm A reaction mixture contains 0.89 atm 12 and 1.77 atm I. Which of the following statements is TRUE concerning this system?
Given the following data, determine the rate law for the reaction below. 2H2 (g) + 2NO(g) → 2H2O(g) + N2(g) Experiment 1 23 [H2] (M) [NO] (M) Initial Rate (M/s) 0.0369 0.0262 0.0248 0.1107 0.0262 0.0774 0.0369 0.0524 0.0992 Rate = k[H2][NO] Rate = k[H2][NO] Rate = k[NO]2 Rate = k[H2][NO]² Rate = k[H2][NO]
Use the appropriate equation to calculate the free energy change for the movement of Nat into the depolarized nerve cell where the membrane potential is +50mV and the Nain/Naout ratio is 7.3/1. Assume the temperature is 37°C. Stop! For full credit: 1. Enter your answer in kJ, kilojoules. 2. Do not put units in the box. 3. Round your answer to the nearest tenth. If your calculator permits, do not round until the end for the sake of continuity. 4. If your answer is negative, include the sign and number with no space.
Your current Vmax (4x10-3 A/S) from the Michaelis-Menten plot has the units of A/s and was determined using 0.1 mg of ADH in a total volume of 1.25 mL. Use the Beer-Lambert equation followed by simple conversion to express your estimated Vmax in (mol )/s per 1 mg ADH. The molar absorptivity of NADH at 340 nm is 6220 L/(mol*cm).
When the following equation of a redox reaction in acidic solution is properly balanced, what are the coefficients for Cr2O72–, Fe2+ H+, Cr3+, Fe3+, and H2O, respectively? __Cr2O72– + __Fe2+ + __H+ --> __Cr3+ + __Fe3+ + __H2O (A) 1, 3, 14, 2, 3, 7; (B) 1, 6, 14, 2, 6, 7; (C) 2, 10, 14, 2, 10, 7; (D) 2, 12, 28, 4, 12, 14
Example The standard half electrode potential for Fe²+ vs SHE is 0.77 V. What is the value of Ee at T = 298K when: [Fe³+] = 0.2 mol l-1 [Fe2+] = 0.05 mol 1-1
AG°xn=-28.6 kJ Given the following equation, H2O(g) + CO(g) → H2(g) + CO2(g) Calculate AG°n for the following reaction. -> 8 H2O(g) + 8 CO(g) 8H2(g) + 8 CO2(g) a -71.5 kJ b -3.57 kJ C +3.57 kJ d +228.8 kJ e -228.8 kJ O O O O O
The distribution of Na* ions across a typical biological membrane is 10 mmol/dm3 inside the cell, and 140 mmol/dm³ outside the cell. At equilibrium, the concentrations across the membrane are equal. What is the Gibbs energy difference across the membrane at 37°C? The stated difference in concentration MUST be maintained by coupling to reactions that have at least your calculated difference of Gibbs energy. Ans: 6.8 kJ/mol

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