You have been the following vector function which describes an electric field. Its your job to figure out the electric flux trough each of the three square sections depicted on the right. a E = 21+x²j a a a a
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Q: ermine whether each statement below about flux is true or false. O The total electric flux for a…
A: Given: determine whether each statement below about flux is true or false.The total electric flux…
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- I need help can you label which one is A,B,C and DConsider the following situation. A positive charge q is located a distance R from a charged wire bent into a circular arc as drawn. The arc has radius R, a net positive charge Q, and an angular extent of 30° (T/6 radians) centered on the same axis as q. 15° a. Calculate the electric field (vector) the arc of wire produces at q's location. Give the vector in component form. The vector only has one component. You should write down in words an argument using the problem's symmetry for this. b. Find the net force (vector) on q by the arc of wire. Give the vector in component form. c. Compare this force to the force produced by a positive point charge Q located a distance R away from q. Which force is greater, (b) or (c), and by what fraction? Show this algebraically.need help on part A, C, D
- Problem 2 Consider the Gaussian surface shown in Figure 2. A uniform external electric field E, having magnitude 3.20 x 103 N/C and parallel to the xz plane with an angle of 36.87° measured from the +x axis toward the +z axis, enters through face 1 (back face). In addition, a uniform electric field E, of magnitude 6.40 x 103 N/C traveling in the same direction as E, , flows outwardly through face 2 (front face). 0,45 m 0,30 m En 0.50 m Figure 2. Gaussian surface in the form of a prism through which two fields pass.Consider the following vector field ? = (??)?̂ + (2??)?̂ + (3??)?̂ a. Compute the curl of this vector field. b. Use your result from (a) to compute the line integral of the vector field along the triangular path shown.Problem 1 Shown on the right is an electroscope. The sphere on the top, the leaves at the bot- tom, and the rod connecting them are made by conducting material. The spherical shell that blocks the influence of external electric fields is also made by conducting material but the contact with the rod is insulated, so that charges will not shuffle between the rod and the spherical shell. The electroscope is first negatively charged by touching the sphere with a negatively charged plastic plate. The leaves spread apart and we remove the plastic plate. We then bring a positively charged glass bar close to the sphere without touching the sphere. What happens to the leaves? Leaves (A) One leaf moves higher, the other lower. (B) Nothing changes to the leaves (C) The leaves spread farther apart. (D) The leaves get closer together. Clearly specify/circle your answer, and give a brief explanation.