2. Two very large flat sheets are oriented parallel to each other and are oppositely charged. The sheets are separated by a distance d. a. Draw a vector showing the electric field at point A due to the negative sheet. Draw a second vector showing E at point A due to the positive sheet. b. What is the net electric field at point A? Hint: does the electric field of a sheet depend on distance? C. Draw two vectors showing & at point B due to the negative sheet and E due to the positive sheet. d. What is the x component of the net electric field at point B? e. Make a graph of the x component of the electric versus X. Ex A + 17 EQ 0 17 Eo x=0 -17 0 B x=d d +1

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Chapter24: Gauss’s Law
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part e please

2. Two very large flat sheets are oriented parallel to each
other and are oppositely charged. The sheets are
separated by a distance d.
a. Draw a vector showing the electric field at point A
due to the negative sheet. Draw a second vector
showing & at point A due to the positive sheet.
b. What is the net electric field at point A? Hint: does
the electric field of a sheet depend on distance?
C. Draw two vectors showing & at point B due to the
negative sheet and E due to the positive sheet.
d. What is the x component of the net electric field at
point B?
e.
Make a graph of the x component of the electric
field versus X.
Ex
+
?
0
?
EQ
x=0
F
-??
0
B
x=d
x
nd
+1
$
Transcribed Image Text:2. Two very large flat sheets are oriented parallel to each other and are oppositely charged. The sheets are separated by a distance d. a. Draw a vector showing the electric field at point A due to the negative sheet. Draw a second vector showing & at point A due to the positive sheet. b. What is the net electric field at point A? Hint: does the electric field of a sheet depend on distance? C. Draw two vectors showing & at point B due to the negative sheet and E due to the positive sheet. d. What is the x component of the net electric field at point B? e. Make a graph of the x component of the electric field versus X. Ex + ? 0 ? EQ x=0 F -?? 0 B x=d x nd +1 $
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