(c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50 µC and the bottom half, insulated from the top half, carried total charge of +7.50 µC?

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Solve part c of the image, include all the procedures to arrive at the result.

c)What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of −7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
A uniformly charged insulating rod of length 15.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 µC.
(a) Find the magnitude of the electric field (in N/C) at 0, the center of the semicircle.
1.88e07
N/C
(b) Find the direction of the electric field at o, the center of the semicircle.
O to the left
O to the right
O upward
O downward
O into the page
O out of the page
(c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50o µC and the bottom half,
insulated from the top half, carried
a total charge of +7.50 µC?
N/C
Transcribed Image Text:A uniformly charged insulating rod of length 15.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -7.50 µC. (a) Find the magnitude of the electric field (in N/C) at 0, the center of the semicircle. 1.88e07 N/C (b) Find the direction of the electric field at o, the center of the semicircle. O to the left O to the right O upward O downward O into the page O out of the page (c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of -7.50o µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? N/C
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