An electric field given by É = 6.4 i - 5.2(y? + 7.3) ĵ pierces the Gaussian cube of edge length 0.200 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube? Gaussian surface (a) Number -1.52672 Units N-m^2/C (b) Number 1.5184 Units N-m^2/C (c) Number i 0.256 Units N-m^2/C
An electric field given by É = 6.4 i - 5.2(y? + 7.3) ĵ pierces the Gaussian cube of edge length 0.200 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube? Gaussian surface (a) Number -1.52672 Units N-m^2/C (b) Number 1.5184 Units N-m^2/C (c) Number i 0.256 Units N-m^2/C
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I just need help with part C. Part C is wrong
![### Electric Flux Through a Gaussian Surface
An electric field is described by the equation:
\[
\vec{E} = 6.4 \hat{i} - 5.2(y^2 + 7.3) \hat{j}
\]
This field intersects a Gaussian cube with an edge length of 0.200 m. The cube is aligned as shown in the accompanying figure, where the axes \(x\), \(y\), and \(z\) are indicated.
#### Problem:
Determine the electric flux through the following faces of the cube:
- (a) Top face
- (b) Bottom face
- (c) Left face
- (d) Back face
- (e) What is the net electric flux through the entire cube?
#### Answers:
- **(a) Top Face:**
- Electric Flux: **-1.52672** \( \text{N·m}^2/\text{C} \)
- **(b) Bottom Face:**
- Electric Flux: **1.5184** \( \text{N·m}^2/\text{C} \)
- **(c) Left Face:**
- Electric Flux: **0.25** \( \text{N·m}^2/\text{C} \)
- **(d) Back Face:**
- Electric Flux: **0** \( \text{N·m}^2/\text{C} \)
- **(e) Net Electric Flux:**
- Total Electric Flux through the Cube: **-8.32E-3** \( \text{N·m}^2/\text{C} \)
#### Diagram Description:
The diagram features a cube labeled "Gaussian surface," with coordinate axes depicted next to it. The electric field components and the orientation of the cube relative to these coordinates are crucial for calculating the flux through each face.
This information helps in understanding how the electric field interacts with a three-dimensional surface, applying the concept of flux in electromagnetism.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42eb3f21-115e-47f2-b59c-753292f0c3d6%2F08866d49-a9e7-43c0-b1b2-6b2eb1119a3c%2Fq03ejit_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Electric Flux Through a Gaussian Surface
An electric field is described by the equation:
\[
\vec{E} = 6.4 \hat{i} - 5.2(y^2 + 7.3) \hat{j}
\]
This field intersects a Gaussian cube with an edge length of 0.200 m. The cube is aligned as shown in the accompanying figure, where the axes \(x\), \(y\), and \(z\) are indicated.
#### Problem:
Determine the electric flux through the following faces of the cube:
- (a) Top face
- (b) Bottom face
- (c) Left face
- (d) Back face
- (e) What is the net electric flux through the entire cube?
#### Answers:
- **(a) Top Face:**
- Electric Flux: **-1.52672** \( \text{N·m}^2/\text{C} \)
- **(b) Bottom Face:**
- Electric Flux: **1.5184** \( \text{N·m}^2/\text{C} \)
- **(c) Left Face:**
- Electric Flux: **0.25** \( \text{N·m}^2/\text{C} \)
- **(d) Back Face:**
- Electric Flux: **0** \( \text{N·m}^2/\text{C} \)
- **(e) Net Electric Flux:**
- Total Electric Flux through the Cube: **-8.32E-3** \( \text{N·m}^2/\text{C} \)
#### Diagram Description:
The diagram features a cube labeled "Gaussian surface," with coordinate axes depicted next to it. The electric field components and the orientation of the cube relative to these coordinates are crucial for calculating the flux through each face.
This information helps in understanding how the electric field interacts with a three-dimensional surface, applying the concept of flux in electromagnetism.
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