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Calculate the frequency, wavelength, and mass equivalence of a 511-keV annihilation photon.

Expert Solution

Given:

The energy of the photon, $E = 511 k e V = 511 \times 10^{3} e V$

We know, $1 e V = 1.6 \times 10^{- 19} J$

So, energy of the photon is,

$\Rightarrow E = 511 \times 10^{3} \times 1.6 \times 10^{- 19} J \Rightarrow E = 817.6 \times 10^{- 16} J$

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