Please make a diagram or graph position according to time for the situation so I can clearly understand. What I mean by (m/s squared)0,29m/s?20,69m/s² Two trains are 9.82km apart. They travel inopposite directions, to each other. Train A has aspeed of 5.87 km/h at departure and anacceleration of 0.29m/s squared. Train B has aspeed of 20.3m/s at the start and an acceleration of0.69m/s squared.

distance between two trains=9.82 kmspeed of train A=5.87 kmh=1.63msAcceleration of trainA=aA=0.29…

Answered: Two trains are 9.82km apart. They…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Please make a diagram or graph position according to time for the situation so I can clearly understand.

What I mean by (m/s squared)
0,29m/s?
2
0,69m/s²

Two trains are 9.82km apart. They travel in
opposite directions, to each other. Train A has a
speed of 5.87 km/h at departure and an
acceleration of 0.29m/s squared. Train B has a
speed of 20.3m/s at the start and an acceleration of
0.69m/s squared.

Expert Solution

Step 1

$d i s \tan c e b e t w e e n t w o t r a i n s = 9.82 k m s p e e d o f t r a i n A = 5.87 \frac{k m}{h} = 1.63 \frac{m}{s} A c c e l e r a t i o n o f t r a i n A = a_{A} = 0.29 \frac{m}{s^{2}} s p e e d o f t r a i n B = 20.3 \frac{m}{s} A c c e l e r a t i o n o f t r a i n B = a_{B} = 0.69 \frac{m}{s^{2}}$