1. Starting with equation (2) above and given values on the picture below, solve the force body diagram pictured for the ratio m,/m2 First be Insert the m (COM) of th Record the loc mg m:g mcomg
1. Starting with equation (2) above and given values on the picture below, solve the force body diagram pictured for the ratio m,/m2 First be Insert the m (COM) of th Record the loc mg m:g mcomg
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you help me solve number 1? Equation two is on the jpg titled expg1.

Transcribed Image Text:1. Starting with equation (2) above and given values on the picture below, solve the force
body diagram pictured for the ratio m,/m2
loon N
dlamps wi
First
be
2 Insert the
(COM) of
Record the lc
r2
mg
m2g
mcomg
2. Now, change the location of the pivot point - moving it to the right of the center of mass
a distance r3. Solve the system pictured below using equation (2) for the mass of the
meter stick. This will be equation (3).
notar
Record
om.
rst 5 g
Record
added
AN
r2
m g
mag
mcomg
CS Scan
nke
WheCOM position so that it
achieved. Record the

Transcribed Image Text:This experiment will investigate the rotational analog of forces in equilibrium – i.e. torques in
equilibrium. Here we will consider the net Torque acting on a rotating mass, Et around a specified
pivot point. A single torque, t, is directly related to an individual force acting on a rotating object:
T =rx F;
|t| = Ir||F|sine = rF1, (1)
where r is the position vector indicating the distance from where the force acts to the pivot point.
Only perpendicular components of force with respect to the r vector will contribute to torque.
Generally speaking net torque will give rise to an angular acceleration a.
Στ- Ια
(general equation)
Equilibrium problems consider the subset of the general equation where there is no rotation; i.e.
a=0.
Στ -0
(equilibrium equation)
(2)
CS Scanned
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