Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 130 kg-m². When one person is standing at a distance of 1.58 m from the center, the carousel has an angular velocity of 0.552 rad/s. However, as this person moves inward to a point located 0.748 m from the center, the angular velocity increases to 0.811 rad/s. What is the person's mass? Number i Units
Angular Momentum
The momentum of an object is given by multiplying its mass and velocity. Momentum is a property of any object that moves with mass. The only difference between angular momentum and linear momentum is that angular momentum deals with moving or spinning objects. A moving particle's linear momentum can be thought of as a measure of its linear motion. The force is proportional to the rate of change of linear momentum. Angular momentum is always directly proportional to mass. In rotational motion, the concept of angular momentum is often used. Since it is a conserved quantity—the total angular momentum of a closed system remains constant—it is a significant quantity in physics. To understand the concept of angular momentum first we need to understand a rigid body and its movement, a position vector that is used to specify the position of particles in space. A rigid body possesses motion it may be linear or rotational. Rotational motion plays important role in angular momentum.
Moment of a Force
The idea of moments is an important concept in physics. It arises from the fact that distance often plays an important part in the interaction of, or in determining the impact of forces on bodies. Moments are often described by their order [first, second, or higher order] based on the power to which the distance has to be raised to understand the phenomenon. Of particular note are the second-order moment of mass (Moment of Inertia) and moments of force.
I'm pretty sure I got the first step right, but I'm really struggling with the second step. I think I set up the equation correctly, but when it comes to actually solving, I'm not getting the steps right. Can you please list out step by step how to solve the equation in part 2, assuming I got that equation right. I've attached the problem, as well as my work.

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at
playground carousel is free to rotate about it's center on frictionless
bearings, and air resistence is
has a moment of inertia of 130 kg.m² When one
negligable. The carousel itself (without riders)
a distance of 1.58 m from the center, the carousel has an angular velocity
person is standing.
of.552 rad/s. However, as this person
mores inward to a point =
located . 148m from the center, the angular velocity
What is the
eson
227
the angolar velocity recreased to - Ellrad/s
persons mass?
I: 130kg.m²
Xo:1.58m
w..552 rad /s
x: 748m
Wp: 811 rad /s
find H
CQUATIONS
Conservation of Angular Homendum: I₁ W₁=I₂ W₂
Parallel Axis I "Ie +mr²
ⒸI₁ = 130 kg⋅ m² + m (1.58)²
I 13
+ 2.4964m
130 куне
I ₂ = 130 kg. m² + m( . 748m) ²
-
mida to
130kg.m² + 1.378m²= 130 + .45375m
131.375m
130.45375m
de 2004
dan A
ERS
I ₂ = 130 kg.m² +₁5595m - poh 45
T₂W₁ = I₂ W₂
LA
(130 kg⋅m² + 2.4964 m) (.552) = (130kg⋅m² +.5595m) (811)
SOLVE FOR H
20
35
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