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Given that the Diameter of Earth is about 7200 miles how many Earths would fit across the sun ?

Given that the Diameter of Earth is about 7200 miles how many Earths would fit across the sun ?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Given that the Diameter of Earth is about 7200 miles how many Earths would fit across the sun ?

 

d. Diameter of the Sun I h d Standing on the beach at sunset, you extend the tip of your finger at your full arm length from your face, covering the Sun. Upon moving your finger around, you find that only about half of its width is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5 inches. You know your arm length to be 28.0 inches You have be told that the Sun is approximately 93 million miles away. Use this information to determine the approximate diameter of the Sun, filling in the table below with the proper quantities measure in meters. 1=½ finger width X Arm length g = eye level d = object height A = angle from eye f= object height from h= Diameter of the Sun %3D %3D distance 93x10 mi level to top of eye level object OR 1.023 0127m
Transcribed Image Text:d. Diameter of the Sun I h d Standing on the beach at sunset, you extend the tip of your finger at your full arm length from your face, covering the Sun. Upon moving your finger around, you find that only about half of its width is needed to completely cover the Sun's diameter. You measure your finger width to be 0.5 inches. You know your arm length to be 28.0 inches You have be told that the Sun is approximately 93 million miles away. Use this information to determine the approximate diameter of the Sun, filling in the table below with the proper quantities measure in meters. 1=½ finger width X Arm length g = eye level d = object height A = angle from eye f= object height from h= Diameter of the Sun %3D %3D distance 93x10 mi level to top of eye level object OR 1.023 0127m
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