5. Use the tape measure to determine r, the distance between the charge and a point the four potential lines (circles) you just drew. r= m 6. Calculate the potential using the formula V = k. 1²/1 Where k = 9 * 10⁹, q=1nC = -1 * 10⁹ and r is your reading from the tape measure. Note: We are using a rounded value for k to simplify the calculations. Here is an example of how to apply the measurements to the calculations. Given: q=-1nC= -1.00* 10-⁹℃ r = 0.269 m k=9.00* 10⁹ V = -32.9V N.m² C²

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So I am doing this practice lab and I think I am just overthinking it for my step number 6. I sure it is as straight forward as it shows but I am just not understanding. So for "r" I have 84.7 cm which is 0.847 m for my first measurement. I think all I have to do is just input it to the formula provided that I have in the photo for step 6. So if i can just get a better example of what it is asking, I would greatly appreciate. I am just slow when it comes to following instructions. 

### Electric Field and Equipotential Lines

**Diagram Description:**

This image illustrates the electric field and equipotential lines around a negative point charge. Key features of the diagram are described below:

1. **Central Charge:**
   - A central circle, representing a negative charge of -1 nC, is shown at the center of the diagram.

2. **Electric Field Lines:**
   - Gray arrows radiate inward, directed towards the central negative charge. The arrows indicate the direction of the electric field, which points towards the charge in the case of negative charges.

3. **Equipotential Lines:**
   - Green concentric circles represent equipotential lines surrounding the charge. These lines are perpendicular to the electric field lines.

4. **Equipotential Values:**
   - The equipotential lines are labeled with values in volts (V), indicating the electric potential along those lines. Moving outward from the center, the potential values are -10.6 V, -6.1 V, and -4.2 V.

5. **Measurement:**
   - A yellow circle indicates a specific measurement point, detailing that it is 84.7 cm away from the charge center. At this point, the electric potential is -2.886 V, as shown in the measuring tool on the left. 

6. **Tool Interface:**
   - A measuring tool on the left displays the equipotential value of -2.886 V, with options to adjust or erase values.

7. **Charge Indicators:**
   - At the bottom, options are available to place additional charges: a positive charge (+1 nC) and a negative charge (-1 nC), along with a sensor option to analyze points in the field.

**Educational Explanation:**

The diagram visually demonstrates important concepts in electrostatics:

- **Electric Field (E-field):** The region around a charged particle where a force would be exerted on other charges. The direction of field lines indicates how a positive test charge would move within the field.
  
- **Equipotential Lines:** These are lines where the electric potential is the same. No work is done when moving a charge along an equipotential line, as there is no differential in potential energy.

The interaction between the electric field lines and equipotential lines exemplifies the principles of electrostatic force and potential energy, fundamental concepts in physics that help explain electromagnetic interactions.
Transcribed Image Text:### Electric Field and Equipotential Lines **Diagram Description:** This image illustrates the electric field and equipotential lines around a negative point charge. Key features of the diagram are described below: 1. **Central Charge:** - A central circle, representing a negative charge of -1 nC, is shown at the center of the diagram. 2. **Electric Field Lines:** - Gray arrows radiate inward, directed towards the central negative charge. The arrows indicate the direction of the electric field, which points towards the charge in the case of negative charges. 3. **Equipotential Lines:** - Green concentric circles represent equipotential lines surrounding the charge. These lines are perpendicular to the electric field lines. 4. **Equipotential Values:** - The equipotential lines are labeled with values in volts (V), indicating the electric potential along those lines. Moving outward from the center, the potential values are -10.6 V, -6.1 V, and -4.2 V. 5. **Measurement:** - A yellow circle indicates a specific measurement point, detailing that it is 84.7 cm away from the charge center. At this point, the electric potential is -2.886 V, as shown in the measuring tool on the left. 6. **Tool Interface:** - A measuring tool on the left displays the equipotential value of -2.886 V, with options to adjust or erase values. 7. **Charge Indicators:** - At the bottom, options are available to place additional charges: a positive charge (+1 nC) and a negative charge (-1 nC), along with a sensor option to analyze points in the field. **Educational Explanation:** The diagram visually demonstrates important concepts in electrostatics: - **Electric Field (E-field):** The region around a charged particle where a force would be exerted on other charges. The direction of field lines indicates how a positive test charge would move within the field. - **Equipotential Lines:** These are lines where the electric potential is the same. No work is done when moving a charge along an equipotential line, as there is no differential in potential energy. The interaction between the electric field lines and equipotential lines exemplifies the principles of electrostatic force and potential energy, fundamental concepts in physics that help explain electromagnetic interactions.
### Educational Website Content: Calculating Electric Potential

**Step-by-Step Instructions:**

**5. Measure Distance (r)**  
- Use the tape measure to determine \( r \), the distance between the charge and a point on any of the four potential lines (circles) you just drew.  
- Record your measurement: \( r = \_\_\_\_\_\_\_\_\_\_ \, \text{m} \)

**6. Calculate the Electric Potential (V)**  
Use the formula:  
\[ V = k \cdot \frac{q}{r} \]

Where:  
- \( k = 9 \times 10^9 \)
- \( q = 1 \, \text{nC} = -1 \times 10^{-9} \, \text{C} \)  
- \( r \) is your measurement from the tape measure.

*Note: We are using a rounded value for \( k \) to simplify the calculations.*

---

**Example Calculation:**

**Given:**  
- \( q = -1 \, \text{nC} = -1.00 \times 10^{-9} \, \text{C} \)  
- \( r = 0.269 \, \text{m} \)  
- \( k = 9.00 \times 10^9 \, \frac{\text{N} \cdot \text{m}^2}{\text{C}^2} \)  

**Calculate the Potential:**  
\[ V = -32.9 \, \text{V} \]

*Note: For this lab, \( V \) represents the actual potential.*

**Solution:**  
Calculate the potential using the formula:  
\[ V = k \cdot \frac{q}{r} \]

\[ \hat{V} = \left( 9.00 \times 10^9 \, \frac{\text{N} \cdot \text{m}^2}{\text{C}^2} \right) \cdot \left( \frac{-1.00 \times 10^{-9} \, \text{C}}{0.269 \, \text{m}} \right) = -33.5 \, \frac{\text{N}}{\text{C}} = -33.5 \, \text{V
Transcribed Image Text:### Educational Website Content: Calculating Electric Potential **Step-by-Step Instructions:** **5. Measure Distance (r)** - Use the tape measure to determine \( r \), the distance between the charge and a point on any of the four potential lines (circles) you just drew. - Record your measurement: \( r = \_\_\_\_\_\_\_\_\_\_ \, \text{m} \) **6. Calculate the Electric Potential (V)** Use the formula: \[ V = k \cdot \frac{q}{r} \] Where: - \( k = 9 \times 10^9 \) - \( q = 1 \, \text{nC} = -1 \times 10^{-9} \, \text{C} \) - \( r \) is your measurement from the tape measure. *Note: We are using a rounded value for \( k \) to simplify the calculations.* --- **Example Calculation:** **Given:** - \( q = -1 \, \text{nC} = -1.00 \times 10^{-9} \, \text{C} \) - \( r = 0.269 \, \text{m} \) - \( k = 9.00 \times 10^9 \, \frac{\text{N} \cdot \text{m}^2}{\text{C}^2} \) **Calculate the Potential:** \[ V = -32.9 \, \text{V} \] *Note: For this lab, \( V \) represents the actual potential.* **Solution:** Calculate the potential using the formula: \[ V = k \cdot \frac{q}{r} \] \[ \hat{V} = \left( 9.00 \times 10^9 \, \frac{\text{N} \cdot \text{m}^2}{\text{C}^2} \right) \cdot \left( \frac{-1.00 \times 10^{-9} \, \text{C}}{0.269 \, \text{m}} \right) = -33.5 \, \frac{\text{N}}{\text{C}} = -33.5 \, \text{V
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