1₁ = 18.0 A 12.0 cm P 16.0 cm 0.250 x 105 T. into the page Zero 0.250 x 10-5 T, out of the page 1.42 x 105 T, out of the page 2.75 x 10-5 T, into the page 5.75 x 10-5 T, into the page 2.75 x 10-5 T, out of the page 5.92 x 105 T. into the page 5.75 x 10-5 T, out of the page 5.92 x 105 T, out of the page 1.42 x 10-5 T, into the page 1₂ = 22.00 A Two insulated and very long wires perpendicular to each other in the same plane carry currents as shown in the figure. Find the magnitude and direction of the net magnetic field these wires produce at point P.

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### Problem Description

Two insulated and very long wires, perpendicular to each other in the same plane, carry currents as shown in the figure. The problem is to find the magnitude and direction of the net magnetic field these wires produce at point P.

### Diagram Details

- There are two wires:
  - Wire 1 carries a current \( I_1 = 18.0 \, \text{A} \) and is oriented vertically from top to bottom.
  - Wire 2 carries a current \( I_2 = 22.0 \, \text{A} \) and is oriented horizontally from right to left.
  
- The distance from Wire 1 to point P is 12.0 cm.
- The distance from Wire 2 to point P is 16.0 cm.
  
### Options for Magnetic Field at Point P

- \( 0.250 \times 10^{-5} \, \text{T}, \) into the page
- Zero
- \( 0.250 \times 10^{-5} \, \text{T}, \) out of the page
- \( 1.42 \times 10^{-5} \, \text{T}, \) out of the page
- \( 2.75 \times 10^{-5} \, \text{T}, \) into the page
- \( 5.75 \times 10^{-5} \, \text{T}, \) into the page
- \( 2.75 \times 10^{-5} \, \text{T}, \) out of the page
- \( 5.92 \times 10^{-5} \, \text{T}, \) into the page
- \( 5.75 \times 10^{-5} \, \text{T}, \) out of the page
- \( 5.92 \times 10^{-5} \, \text{T}, \) out of the page
- \( 1.42 \times 10^{-5} \, \text{T}, \) into the page

This educational problem involves calculating the magnetic field at a point due to perpendicular current-carrying wires using the right-hand rule and combining their effects vectorially.
Transcribed Image Text:### Problem Description Two insulated and very long wires, perpendicular to each other in the same plane, carry currents as shown in the figure. The problem is to find the magnitude and direction of the net magnetic field these wires produce at point P. ### Diagram Details - There are two wires: - Wire 1 carries a current \( I_1 = 18.0 \, \text{A} \) and is oriented vertically from top to bottom. - Wire 2 carries a current \( I_2 = 22.0 \, \text{A} \) and is oriented horizontally from right to left. - The distance from Wire 1 to point P is 12.0 cm. - The distance from Wire 2 to point P is 16.0 cm. ### Options for Magnetic Field at Point P - \( 0.250 \times 10^{-5} \, \text{T}, \) into the page - Zero - \( 0.250 \times 10^{-5} \, \text{T}, \) out of the page - \( 1.42 \times 10^{-5} \, \text{T}, \) out of the page - \( 2.75 \times 10^{-5} \, \text{T}, \) into the page - \( 5.75 \times 10^{-5} \, \text{T}, \) into the page - \( 2.75 \times 10^{-5} \, \text{T}, \) out of the page - \( 5.92 \times 10^{-5} \, \text{T}, \) into the page - \( 5.75 \times 10^{-5} \, \text{T}, \) out of the page - \( 5.92 \times 10^{-5} \, \text{T}, \) out of the page - \( 1.42 \times 10^{-5} \, \text{T}, \) into the page This educational problem involves calculating the magnetic field at a point due to perpendicular current-carrying wires using the right-hand rule and combining their effects vectorially.
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