Given that the Diameter of Earth is about 7200 miles, how many Earths would fit across theSun?You turn toward the east, seeing the full moon rising. You find that half of your finger tip atarm's length also covers the diameter of the Moon! Given that the diameter of the Moon is about2160 miles, approximately how far from Earth is the Moon in miles and km according to yourcalculations? Table 2: Length UnitsMillimeters | CentimetersMetersKilometersInchesFeetYardsMileskmyd0.003281 | 0.001094 6.21e-070.393701 0.032808 0.010936| 0.0000063.28084 | 1.093613 | 0.00062139370.08 3280.84 | 1093.613 0.6213710.083333 0.027778 0.000016mmcmminftmi0.0010.0110.10.0000010.039371010.000011000100000025.4304.8914.41001000000.00110.0000250.0003050.00091439.370082.5430.4891.4410000.02540.30480.914411236130.333333 0.0001890.00056811609344160934.41609.3441.60934463360528017601

Hey, there are multiple questions posted; we are authorized to answer one question at a time, since…

Answered: Given that the Diameter of Earth is…

Science

Physics

Given that the Diameter of Earth is about 7200 miles, how many Earths would fit across the Sun?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Convert 4800 meters into feet. Round your answer to the near...
need help solving this question
A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]
Approximately how many inches are in 2500 millimeters?
(0.59 x 10^-6 x 0.3) / (0.36 x 10^-3) when you calculate that don't you get 4.9166 x 10 ^-4 m not 4.92 x 10^-2 m?
The Earth has a mass of 5.98 x 10 ^24 kg and a radius of 6.38 x 10^ 6 m. The density of the earth is _____. Hint: Use the formula of a sphere in computing for its volume (Volume of Sphere, V = (4/3)πr^3)
need help with this question
This was somewhat helpful, but my radius is not 3.5km it's 5km. This is not the answer to my question, it is only similar to it. I can not interpret your handwriting to follow along to answer for my question.
Convert 5 kilometers into meters.
The average radius of Earth is typically accepted to be approximately 6371 km. Using this dimension, determine the surface area in km2 and the volume in km3. Give both answers in scientific notation to one decimal place.
How many years older will you be 1.30 billion seconds from now? (Assume a 365-day year.) dont provide handwritten solution
Use Kepler's Law, which states that the square of the time, T, required for a planet to orbit the Sun varies directly with the cube of the mean distance, a, that the planet is from the Sun.Using Earth's time of 1 year and a mean distance of 93 million miles, the equation relating T (in years) and a (in million miles) is 804375T2=a3.Use that relation equation to determine the time required for a planet with mean distance of 206 million miles to orbit the Sun. Round to 2 decimal places. years