A. Which of these statements about a dipole are correct? Select all that are true. I: The electric field at any location in space, due to a dipole, is the vector sum of the electric field due to the positive charge and the electric field due to the negative charge. II: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to III: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to 1 • IV: A dipole consists of two particles whose charges are equal in magnitude but opposite in sign. V: The net electric field due to a dipole is zero, since the contribution of the negative charge cancels out the contribution of the positive charge. A. I B. II C. III D. IV E. V B. A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 1.2 nm along the y-axis. The +e charge is on the -y-axis and the -e charge is on the +y-axis. A proton is located at < 1.2e - 05, 0, 0 > m. What is the net electric field at the location of the proton? 0 ) N/C ' ( 0 7.29-10-7 1077), 0) (0,0,0) m C. Determine where you should place an electron (in m) so that the net force (from the dipole and the electron) on the proton will be zero.

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Part B and C are incorrect. Please help.

A. Which of these statements about a dipole are correct? Select all that are true.
I: The electric field at any location in space, due to a dipole, is the vector sum of the electric field due to the positive charge and the electric field due to the
negative charge.
II: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to
III: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to
1
•
IV: A dipole consists of two particles whose charges are equal in magnitude but opposite in sign.
V: The net electric field due to a dipole is zero, since the contribution of the negative charge cancels out the contribution of the positive charge.
A. I
B. II
C. III
D. IV
E. V
B. A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 1.2 nm along the y-axis. The +e charge is
on the -y-axis and the -e charge is on the +y-axis. A proton is located at < 1.2e - 05, 0, 0 > m. What is the net electric field at the location of the proton?
0 ) N/C
'
( 0 7.29-10-7
1077), 0)
(0,0,0)
m
C. Determine where you should place an electron (in m) so that the net force (from the dipole and the electron) on the proton will be zero.
Transcribed Image Text:A. Which of these statements about a dipole are correct? Select all that are true. I: The electric field at any location in space, due to a dipole, is the vector sum of the electric field due to the positive charge and the electric field due to the negative charge. II: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to III: At a distance d from a dipole, where d >> s (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to 1 • IV: A dipole consists of two particles whose charges are equal in magnitude but opposite in sign. V: The net electric field due to a dipole is zero, since the contribution of the negative charge cancels out the contribution of the positive charge. A. I B. II C. III D. IV E. V B. A dipole is centered at the origin, and is composed of particles with charges +e and -e, separated by a distance 1.2 nm along the y-axis. The +e charge is on the -y-axis and the -e charge is on the +y-axis. A proton is located at < 1.2e - 05, 0, 0 > m. What is the net electric field at the location of the proton? 0 ) N/C ' ( 0 7.29-10-7 1077), 0) (0,0,0) m C. Determine where you should place an electron (in m) so that the net force (from the dipole and the electron) on the proton will be zero.
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