Here are the equations I only need help with part e please **Newton's Second Law and Tension Analysis****Equations:**(b) Newton’s Second Law for \( m_1 \) in terms of the tension \( T \) and the weight \( m_1g \) can be written as:\[ \sum F_y = T - m_1g = m_1a_1 \](c) Newton’s Second Law for \( m_2 \) in terms of the tension \( T \) and the weight \( m_2g \) can be written as:\[ \sum F_y = T - m_2g = m_2a_2 \]**Question:**(d) How are \( a_1 \) and \( a_2 \) related? What are the directions of \( a_1 \) and \( a_2 \)?- A. \( a_1 \) is greater than \( a_2 \)- B. \( a_1 \) is less than \( a_2 \)- C. \( a_1 \) and \( a_2 \) have the same magnitude and direction- D. \( a_1 \) and \( a_2 \) have the same magnitude but opposite directions**Correct Answer:** D. \( a_1 \) and \( a_2 \) have the same magnitude but opposite directions.**Consider:**How will the equations from part (b) and (c) change considering the relationship between \( a_1 \) and \( a_2 \)? **Solve with Numerical Values****Block 1** has a mass of 2.5 kg and **Block 2** has a mass of 4 kg.(e) Using the rewritten equations from part (b) and part (c) and part (d), find the magnitude of the acceleration of the two blocks.- \( a = \frac{2}{\sqrt{6}} \) m/s\(^2\)(f) Calculate the tension in the string.- \( T = \frac{6}{\sqrt{5}} \) N**Think:** How would the answers for part (e) and (f) change if instead you chose downward as positive and upward as negative direction?

here, a1=T-m1gm1 Anda2=T-m2gm2And as…

Answered: Block 1 has mass 2.5 kg and b (e) Using…

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Block 1 has mass 2.5 kg and b (e) Using the rewritten equatic acceleration of the two blocks a= 2.6 X

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Here are the equations I only need help with part e please

**Newton's Second Law and Tension Analysis**

**Equations:**

(b) Newton’s Second Law for \( m_1 \) in terms of the tension \( T \) and the weight \( m_1g \) can be written as:
\[ \sum F_y = T - m_1g = m_1a_1 \]

(c) Newton’s Second Law for \( m_2 \) in terms of the tension \( T \) and the weight \( m_2g \) can be written as:
\[ \sum F_y = T - m_2g = m_2a_2 \]

**Question:**

(d) How are \( a_1 \) and \( a_2 \) related? What are the directions of \( a_1 \) and \( a_2 \)?

- A. \( a_1 \) is greater than \( a_2 \)
- B. \( a_1 \) is less than \( a_2 \)
- C. \( a_1 \) and \( a_2 \) have the same magnitude and direction
- D. \( a_1 \) and \( a_2 \) have the same magnitude but opposite directions

**Correct Answer:** D. \( a_1 \) and \( a_2 \) have the same magnitude but opposite directions.

**Consider:**
How will the equations from part (b) and (c) change considering the relationship between \( a_1 \) and \( a_2 \)?

**Solve with Numerical Values**

**Block 1** has a mass of 2.5 kg and **Block 2** has a mass of 4 kg.

(e) Using the rewritten equations from part (b) and part (c) and part (d), find the magnitude of the acceleration of the two blocks.

- \( a = \frac{2}{\sqrt{6}} \) m/s\(^2\)

(f) Calculate the tension in the string.

- \( T = \frac{6}{\sqrt{5}} \) N

**Think:** How would the answers for part (e) and (f) change if instead you chose downward as positive and upward as negative direction?

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