You have been provided with the results of a sequence analysis of the gene for a fish with a small heart and one with a wild type heartRed-TBlue-CGreen-ABlack GSmall HeartWild type HeartWwwType the sequence of the small heart gene, reading from left to right:|toWhat is the base change that has resulted in the small heart phenotype?

Chromatograms are depicted in colourful peaks which are used to represent the sequence of bases in…

Answered: You have been provided with the results…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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In the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cM
In c. elegans, genetics model organism, movement problems (unc) and small body size (sma) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (unc+ and sma+). A worm homozygous for movement problems and small body is crossed with a worm homozygous for the wild-type traits. The F1 have normal movement and normal body size. The F1 are then crossed with worms that have movement problems and small body size in a testcross. The progeny of this testcross is: Normal movement, normal body size 210 Movement problems, normal body size 9 Normal movement, small body size 11 Movement problems, small body size 193 a)From the test cross results, can you tell if the two genes are on the same chromosome or not? Explain your reasoning. b)What phenotypic proportions would be expected if the genes for round eyes and white body were located on different chromosomes? (please explain hot to get to these conclusions)
The Turner Kieser Syndrome (or nail patella syndrome) is a dominant human disease (prevalence about 1/100.000), which impairs the normal development of, nails and kneecaps (patella). In the following study the mutant allele for this gene is noted "M" and the wild type allele "m". On the family tree below black symbols (circles for women and squares for men) indicate people suffering from KSS and open symbols represent healthy persons. Moreover, all individuals have been genotyped at the locus controlling blood type ([O] : ii ; [A] : Iª_ ; [B] : /B_ ; [AB] : /A/B) 1 2 Reminder 3 ilB iIB 2 3 O iIB IB iIB 7 O ii iIB IB IA ii ii Z(0) = Log10 6 4 What to conclude from this value of Z ? 5 ilA ilA ii 8 9 probability if linkage probability if independant 10 2 ilB Calculate the LOD-score Z (Logarithm Of Odds) for a genetic distance set to 10 cM (hence a recombination frequency of 0 = 0,1). 11 12 13 = ii iIB ii ii ii iIB IB 14 15 16 Log10 L (0<0,5) L (0=0,5)
HOW DO I SOLVE THIS STEP BY STEP: Recent studies suggest that having the A blood type increases the risk of serious complications for patients suffering from COVID-19. Sarah doesn't know her blood type, but she knows her father is type O and her mother is type AB. What is the probability, from 0 to 100 percent, that Sarah is blood type A? Enter a single whole number from 0 to 100. If you think the answer is a fraction, then round to the nearest whole number.
Below is a pedigree showing transmission of a disease; affected individuals are indicated by solid circles or boxes. Represented below the pedigree are two nylon membranes; DNA samples from each individual in the pedigree were spotted in identical fashion on each membrane. Each individual's DNA appears directly below his or her position in the pedigree. Each membrane was hybridized with allele specific oligonucleotides that detect the two alternative alleles of a single SNP locus (ASO 1 and ASO 2). Positive hybridization is represented as a filled circle and lack of hybridization is represented as an open circle. I 11 III IV V ASO 1 ASO 2 To 1 2 3 4 5 6 a. What is the mode of transmission of this disease? 12 b. Which SNP allele (ASO1 or ASO2) is originally linked to the disease gene? c. Draw a diagram of the event that gave rise to the genotype of individual IV-5. d. Individual V-1 is an unborn fetus. If the SNP locus is 10 CM from the disease locus, what is the likelihood that he will…
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QTL mapping and GWA (association) mapping are two different methods used to identify genes that affect complex traits. For each of the following statements, choosewhether it applies to QTL mapping, association mapping, or both.whether it applies to QTL mapping, association mapping, or both.
Three tomato plants vary in the shape of their leaves: A has smooth edges on its leaves, B has wavy edges on its leaves, and C has smooth edges with bumps in the center of the leaf. Their genomes are the presence of three siRNAs as shown in the table below. Each plant is also tested to see if it is susceptible to attack by herbivorous beetles. Plant siRNA 1 siRNA 2 siRNA 3 Susceptible to Beetles A Yes No No Yes B Yes Yes No Yes C Yes No Yes No Part A: Identify the role of each siRNA. Explain how the siRNAs do their jobs. Part B: Decipher the connection between the phenotypes and susceptibility to beetles and explain how you deciphered this.
Sickle cell anemia is a genetic disease most common in those of African ancestry that results from the mutation of a single basepair. This mutation results in a change to the hemoglobin protein. In this experiment, “S” will represent the normal allele and “s” thesickle allele. They are codominant alleles. Therefore, SS is normal, Ss is not fatal but mildly symptomatic, and ss is debilitating,painful, and often fatal. After hundreds or even thousands of generations, both alleles are still common in those of African ancestry. How would you explain this?
You are interested if whether several genes of a certain species of beetle assort independently. So, you conduct several generations of matings, and after you have collected all your data, you are ready to analyze your results. You conduct a Chi2 test to test your hypothesis. You have 6 groups and calculate a Chi? = 13.22. Given that the critical value at 0.05 level of %3D significance = 11.07 at df = 5, %3D (A) State your null hypothesis. (B) Should you accept or reject your null hypothesis? (C) Why did you arrive your decision in (B)?

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