Write a program that asks the user to enter a year, and then displays whether that year is a leap year or not. Note that a year is a leap year if the year is a multiple of 400, or it is a multiple of 4 and not a multiple of 100.
My typed my Java Code & question is screenshot-
import java.util.Scanner;
public class SortedNames {
public static void main(String[] args) {
String name1;
String name2;
String name3;
Scanner keyboard=new Scanner(System.in);
System.out.print("Please Enter First Name: ");
name1=keyboard.nextLine();
System.out.print("Please Enter Second Name: ");
name2=keyboard.nextLine();
System.out.print("Please Enter Third Name: ");
name3=keyboard.nextLine();
if((name2.compareToIgnoreCase(name1)<0)&&(name2.compareToIgnoreCase(name3)<0))
{
System.out.println(name2);
}
if((name1.compareToIgnoreCase(name2)<0)&&(name1.compareToIgnoreCase(name3)<0))
{
System.out.println(name1);
}
if((name3.compareToIgnoreCase(name1)<0)&&(name3.compareToIgnoreCase(name2)<0))
{
System.out.println(name3);
}
}
}
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