### Question:Why is a large negative free energy change a good candidate for a controlling step in a metabolic pathway while a step in a metabolic pathway with a ΔG ≈ 0 is NOT? Be sure to explain your answer.### Explanation:In metabolic pathways, steps with a large negative free energy change (ΔG) often serve as control points because they are essentially irreversible under physiological conditions. This irreversibility means that once the pathway reaches this step, the reaction is committed to proceed in a specific direction. Therefore, these steps can be tightly regulated, ensuring that metabolic flow is responsive to cellular demands and environmental conditions.On the other hand, steps with a ΔG ≈ 0 are near equilibrium and reversible. They do not significantly impact the overall directionality of the pathway because small changes in substrate or product concentrations can easily reverse the reaction. Therefore, these steps are not effective control points, as they don’t commit the flow of metabolites in the same manner. Control of flux through these reactions is weak, so they are less often the targets of regulation.

The change in free energy which is also said as delta G is associated with life's metabolic energy…

Answered: Why is a large negative free energy…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The first question 7
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The enzyme -catalyzed reaction ratewill be increased if the energy level of ES can be increased by all EXCEPT: destabilization of ES by strain loss of entropy due to binding of E and S. destabilization of ES by distortion destabilization of ES by solvation destabilization of ES by electrostatic effects a. b. с. d. е.
The covalent catalytic mechanism of an enzyme depends on a single active site Cys whose pK is 8. A mutation in a nearby residue alters the micro environment so that this pK increases to 10. Would the mutation cause the reaction rate to increase or decrease? Explain.
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Why is a large negative free energy change a good candidate for a controlling step in a metabolic pathway while a step in a metabolic pathway with a AG 2 0 is NOT? Be sure to explain your answer.