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Which of these compounds would not show up under UV? O 1-(3-methoxyphenyl)ethanol O Eugenol O Anisole

Which of these compounds would not show up under UV? O 1-(3-methoxyphenyl)ethanol O Eugenol O Anisole

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please help me I am trying to study for an upcoming final and was confused on some of the practice problems.
### Identifying Compounds through UV Spectroscopy #### Question: **Which of these compounds would not show up under UV?** - **1- (3-methoxyphenyl)ethanol** - **Eugenol** - **Anisole** - **Phenol** - **4-tertbutylcyclohexanone** #### Explanation: UV (ultraviolet) spectroscopy is a method used to observe compounds that can absorb UV light, typically those with conjugated systems or aromatic rings. Organic compounds containing such features generally display peaks in the UV region. 1. **1- (3-methoxyphenyl)ethanol**: This compound has a methoxyphenyl group, indicating an aromatic ring system. Consequently, it will absorb UV light and show up under UV spectroscopy. 2. **Eugenol**: Eugenol is known for its aromatic ring and conjugated double bonds, meaning it will also strongly absorb UV light and be visible under UV detection. 3. **Anisole**: Anisole contains an aromatic ring with a methoxy substituent, which also absorbs UV light effectively and will show up under UV light. 4. **Phenol**: Phenol, having an aromatic ring with a hydroxyl group, has strong absorption in the UV region due to the pi-electronic system and will be detected under UV light. 5. **4-tertbutylcyclohexanone**: This compound lacks an aromatic ring and instead has a saturated cyclic ketone structure. Ketones without conjugation do not typically absorb in the UV-visible region efficiently, thus this compound would likely not show up under UV light. ### Conclusion: **4-tertbutylcyclohexanone would not show up under UV.**
Transcribed Image Text:### Identifying Compounds through UV Spectroscopy #### Question: **Which of these compounds would not show up under UV?** - **1- (3-methoxyphenyl)ethanol** - **Eugenol** - **Anisole** - **Phenol** - **4-tertbutylcyclohexanone** #### Explanation: UV (ultraviolet) spectroscopy is a method used to observe compounds that can absorb UV light, typically those with conjugated systems or aromatic rings. Organic compounds containing such features generally display peaks in the UV region. 1. **1- (3-methoxyphenyl)ethanol**: This compound has a methoxyphenyl group, indicating an aromatic ring system. Consequently, it will absorb UV light and show up under UV spectroscopy. 2. **Eugenol**: Eugenol is known for its aromatic ring and conjugated double bonds, meaning it will also strongly absorb UV light and be visible under UV detection. 3. **Anisole**: Anisole contains an aromatic ring with a methoxy substituent, which also absorbs UV light effectively and will show up under UV light. 4. **Phenol**: Phenol, having an aromatic ring with a hydroxyl group, has strong absorption in the UV region due to the pi-electronic system and will be detected under UV light. 5. **4-tertbutylcyclohexanone**: This compound lacks an aromatic ring and instead has a saturated cyclic ketone structure. Ketones without conjugation do not typically absorb in the UV-visible region efficiently, thus this compound would likely not show up under UV light. ### Conclusion: **4-tertbutylcyclohexanone would not show up under UV.**
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