Which of the following is true? @Stan (x)sec (x)dx = sec (x) 2sec7(x), sec (x) + C 6. 7 O Stan*wlsec*d< = tanflx) , tan'cw) , tant9(x Jtan (x)sec(x)dx= tan°(x) , tan'(x) tan1(x) 10 + C 6. 4 © - Scot (x)csc®(x)dx = csc°(x) _ 2csc'(x), csc°(x) , c csc (x) 2csc7(x), csc (x) + C 7. All for the above Jsin (x)cos (x)dx = - Cos°(x) , cos°(x) _ cos (x) + C 10 4.

Q: Find f'(x) for f(x) = A f'(x) - B f'(x) = © f(x)= 2x+cos²x tanx 2-2sinxcosx tanx 2x+cos²x sin²x…

A: Given: The function fx=2x+cos2xtanx Find the derivative of the given function Formula used: The…

Q: Find g'(x) if g (x) = 5√x tan x. 5(2 cot x+tan x) 2√x 5 tan x(2x sec x+1) 2√x 5(x sec² x+2 tan x)…

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Q: Let Find f(x)\x= = ". y = f(x) = 31 sec x + 18 tan x 31 sec x 18 tan x d dx -f(x)\ x= 1 *

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Q: tan (x) = sec (x)

A: We know that  tan(x) = sin(x)/cos(x)  Sec(x) = 1/cos(x)  So ,  sin(x)/cos(x) = 1/cos(x)

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Q: Find the critical point of the function f(x) = 3x² – 12x Answer:

A: We will find out all the required values.

Q: Differentiate. f(x) = x cos(x) sin(x) (please write it out on paper)

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Q: Does cot(x) + tan(x) = csc(x) * sec(x) ?

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Q: If f(x) f'(x) = = COs x 4 tan x, then f'(4) = Check Answer

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Q: f(x)=(6+x^3)^cos x Explain with steps

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Q: let f(x) = { x3 tan-1(1/x) if x cannot = 0                 { 0 if x=0  determine whether f'(0)…

A: We can solve the given problem using differentiation of given function.

Q: Differentiate. Fx) = 7V sin(x) f '(x) = Need Help? Read It Submit Answer Practice Anoth 2. -/1…

A: Solving Q1 Given:

Q: What is the second derivative of f (x) =csch¬'(tan(x))? A f"(x)=- sec2(x) B) None of the given…

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Q: Differentiate. V = 3 - sec(x) tan(x)

A: The given function y is in the quotient form. Apply the quotient rule formula

Q: Let f(x) = tan ¹(sin(8x)) f'(x) = > Next Question

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Q: Find f" (x) if f (x) = tan(x² − 1). ○ 2 sec² (x² - 1) ○ 2 sec² (x² − 1) (1 + 4x² tan(x² − 1)) ○ 2…

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Q: Let f(x) = (7 sin x + 2 cos x)tan-lx f'(x) = %3D

A: topic - derivatives

Q: Show that_(csc(x)) = −csc(x) cot(x). dx d (csc(x)) = dx || = dx sin²(x) 1 sin(x) 1 = = -csc(x)…

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Q: Find f. f"(x)  =6 x + Sin x

A: Given: f"x=6x+sinx we know that f'x=∫f"xdx                                      ..1 so, by using…

Q: If f(x) f'(x)= = 3x sin x cos x, find Find f'(5): =

A: 1) f(x)=3 sinx cosx 2) f(x)=8cosx+6tanx.

Q: 4 tan(x) Let f(x) -. Find the following: 4x sec2 (x) – 4 tan(x) 1. f'(x)= %3D 2 2. f'(1)= %3D

A: We know quotient rule for differentiation is  ddxfxgx=gxdfxdx-fxdgxdxgx2

Q: Let f(x) f'(x) = 2 cos x + 7 tan x 2 sin(x) + 7 sec²(x) 1' (5) = 6

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Q: Let Find: f'(x) = f'(8π): - f(x) = 9 tan(x) +7 sec(x)

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Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

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