Let f(x) f'(x) = 2 cos x + 7 tan x 2 sin(x) + 7 sec²(x) 1' (5) = 6

Q: Let f(x) = 12 sin x + 11 cos x f'(x) = f'(꽃) =D

A:

Q: Find f' (x) for 8 sin(x) f(x) = -; 7x2 – 8 sin(x) s'(x) = |

A:

Q: If f(x) = = sin (3 – x), then f'(0) O 6 sin 3 cos 3 O 6 cos 3 O -2 sin 3 cos 3 O -2 cos 3 -2 cos O 2…

A: f(x)=sin2(3-x)

Q: Find f'(x) if ƒ (x) = 6 cos x + 10 sin x. S'(x) =|

A:

Q: Let f(x) 4 cos x + 2 tan x f' (æ) = r(금)- f'

A:

Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

A:

Q: If f(x)= f'(x) = f'(4) = = 3 tan x X " then

A:

Q: Let f(x) = f'(x) = - - 9 cos x + 4 tan x ƒ'( - 7) = =

A:

Q: If f(x) ƒ'(x) = f'(1) = = cos x – 5 tan x, then

A: Given that, f(x)=cosx-5tanx

Q: Find f'(x) if f (x) = 2 cos x + 3 sin x. f'(x) =

A:

Q: If f(x) = cos x 5 tan x, then ƒ'(x) = ƒ'(1) =

A:

Q: Let f(x) = - 9 cos (sin(x*)). Then f'(x) = Preview

A:

Q: Find f. f ''(?) = sin(?) + cos(?),    f(0) = 5,    f '(0) = 2 f(?) =

A: Given that        f"( θ) = sin(θ)+cos(θ)  The initial condition is f(0)=5 and f'(0)=2 We have to…

Q: Let f(x) = tan ¹(sin(8x)) f'(x) = > Next Question

A:

Q: Let h(x) = tan(3x + 4). Then h' (2) is and h'' (2) is

A: The function is given by hx = tan3x+4 To evaluate: The values of h'2 and h''(2)

Q: If f(x) f'(x) = f'(4) = = 4 sin x 3 + cos x " then

A:

Q: Find f'(x) if f (x) = 3 cos x + 8 sin x. f'(x) =

A: We need to differentiate the given Function.

Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Find f''(x) if f(x)=ex cos(x)+x3

A: Find f''(x) if f(x)=ex cos(x)+x3

Q: Let f'(z)= 8cosx-7sind 2 f'() = 0 f(x) = 8 sin x + 7 cos x

A:

Q: If f(x) = f'(x) = f'(1) = 5 sin x 3+ cos x then

A:

Q: Let f(x) = 8x sin ¹(x). Find f'(x). f'(x) = Find f'(0.4). f' (0.4) =

A: Let To find .To find .

Q: = 5 sec x tanx %3D

A: Please refer to the image below

Q: If f(x) f'(x)= = 3x sin x cos x, find Find f'(5): =

A: 1) f(x)=3 sinx cosx 2) f(x)=8cosx+6tanx.

Q: Find f' (x) for 7 sec(r) f(x) = 4(1 + 5 tan(æ)) f' (x) = ||

A:

Q: Find f. f ''(?) = sin ? + cos ?,    f(0) = 1,    f '(0) = 3

A:

Q: f' (x) = r(농) =

A:

Q: If f(x) ƒ'(x) = f'(2) = 4 sin x 3 + cos x then

A: derivative

Q: If f(x) = f'(x) = = f'(4) = 3 tan x, then -sin(x) - 3 sec²(x) COS X >

A: we need to find out the derivative for the given function

Q: Find f'(x) = = 4-5 sin(x) cos²(x) f(x) = -4 sin(x) + 5 cos(x)

A: Given : f(x)=-4sin(x)+5cos(x)   To Find : f'(x)

Q: Let Find: f'(x) = f'(8π): - f(x) = 9 tan(x) +7 sec(x)

A:

Q: Let f(x) = sin(z))". Find (1). (1).

A:

Q: -3 tan x, then f'(x) = -sin(x) - 3 sec²(x) To two decimal places, = COS X f'(2) = - HI

A:

Q: find where f'(c)=0 f(x)=-cos4x

A: Given, function

Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

A:

Q: The derivative of the function f (x) = 3 sin“ x is Select one: O f'(x) = 12 cos³x O f'(x) = 12 sin³…

A: dsinxdx = cosx

Q: If f(x) = cos(x), what is f'(x) ? O -sin(x) O cos(x) O -cos(x) O sin(x)

A: