FIND F'(x) F(x) = 2 tanx 1+cosx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Need help
**Objective:** Find the derivative \( f'(x) \).

**Function:** 
\[ f(x) = \frac{2 \tan x}{1 + \cos x} \]

**Instructions:**

1. **Identify the function** given and observe that it is a quotient, which means the quotient rule is likely a helpful method to find the derivative.
   
2. **Apply the Quotient Rule**: If you have a function of the form \(\frac{u(x)}{v(x)}\), the derivative is given by:
   \[
   f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2}
   \]
   where \( u(x) = 2 \tan x \) and \( v(x) = 1 + \cos x \).

3. **Differentiate \(u(x)\) and \(v(x)\)**:
   - \( u'(x) = 2 \sec^2 x \) (derivative of \( \tan x \) is \( \sec^2 x \))
   - \( v'(x) = -\sin x \) (derivative of \( \cos x \) is \( -\sin x \))
   
4. **Substitute back into the Quotient Rule formula** to find \( f'(x) \).
Transcribed Image Text:**Objective:** Find the derivative \( f'(x) \). **Function:** \[ f(x) = \frac{2 \tan x}{1 + \cos x} \] **Instructions:** 1. **Identify the function** given and observe that it is a quotient, which means the quotient rule is likely a helpful method to find the derivative. 2. **Apply the Quotient Rule**: If you have a function of the form \(\frac{u(x)}{v(x)}\), the derivative is given by: \[ f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2} \] where \( u(x) = 2 \tan x \) and \( v(x) = 1 + \cos x \). 3. **Differentiate \(u(x)\) and \(v(x)\)**: - \( u'(x) = 2 \sec^2 x \) (derivative of \( \tan x \) is \( \sec^2 x \)) - \( v'(x) = -\sin x \) (derivative of \( \cos x \) is \( -\sin x \)) 4. **Substitute back into the Quotient Rule formula** to find \( f'(x) \).
Expert Solution
Step 1

To differentiate the given function.

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning