Find f'(x) for f(x) = A f'(x) - B f'(x) = © f(x)= 2x+cos²x tanx 2-2sinxcosx tanx 2x+cos²x sin²x tanx(2+2cosx) - (2x + cos²x)(sec²x) tan²x (2x + cos²x)sec²x-tanx(2-2sinxcosx) tan²x D Some other answer

Q: Find (f^-1)’(0) if f(x)=x+sin(2x)

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Q: Let f'(x)= = f(x) = x² tan ¹(7x)

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Q: Let f(x) 4 cos x + 2 tan x f' (æ) = r(금)- f'

A:

Q: Determine f '(x) for function f(x)= x2 tan x

A: Firstly, we use product rule of differentiation, which is (uv)'=uv'+u'v as shown on board.

Q: Let f'(x) = f'( 5 ) = f(x) = 3 sin x + 12 cos x

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Q: / If f(x) = 2x (Sinx+cosx) find. f'(x) = ' (5) =

A: Given function  f( x ) = 2x( sinx + cosx )

Q: f(x)=x+sinx / x2+cosx f '(x)=?

A: Given function: Now,

Q: If A and B are constants, find where f''(x) = 0 I= f(x) = 9 Ar² + 7. Bx³

A: Since you have posted multiple questions i can do first question as per our company guidelines…

Q: f(x) = 8 cos x 5 tan x.

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Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Find f''(x) if f(x)=ex cos(x)+x3

A: Find f''(x) if f(x)=ex cos(x)+x3

Q: If f(x) f'(æ) = cos x – 7 tan x, then

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Q: 1 If f(x) = 8 tan¯¹(8 sin(2x)), f'(x) =

A: Differentiate

Q: et f(x)=-11sin x+3 cos x f' (x)=?

A: f(x)=-11sin x+3 cos x this is given  we have to differentiate the function  dsinx/dx = cosx…

Q: 2x2 tan x f(x) sec x

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Q: f' (x) = r(농) =

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Q: Let f'(x) = f(x) = V cos(eztsin(2=)) 4.

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Q: Find f'(x) = = 4-5 sin(x) cos²(x) f(x) = -4 sin(x) + 5 cos(x)

A: Given : f(x)=-4sin(x)+5cos(x)   To Find : f'(x)

Q: IF g(x) = sin(x), then g'(x) = cos (x) 9₁ (3) = IF F(X) = (sin x + 8 cos x, then F'(x) = 6 COS (X) -…

A: Since you have posted a question with multiple question, we will solve first two question for you…

Q: Let f(x)=(6sinx+2cosx)tan−1x f'(x) =

A: Consider the function

Q: f(x) = 7 sinx+ 5 cos x

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Q: f'(x) = f(x) = cos(2x + 3)

A: Given query is to find the derivative.