Find f" (x) if f (x) = tan(x² − 1). ○ 2 sec² (x² - 1) ○ 2 sec² (x² − 1) (1 + 4x² tan(x² − 1)) ○ 2 sec² (x² - 1) (1 + tan(x² − 1)) ○ 2 sec (x² − 1) (sec (x² − 1) + 4x² tan(x² − 1)) O None of these

Q: Let f'(x)= = f(x) = x² tan ¹(7x)

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Q: If f(x) = tan (3x), then f'(x) = (A) 12 tan (3x) sec?(3x) (B) 4 tan (3æ) sec2(3x) (C) 12 tan (3x)…

A: derivative

Q: Let Find f(x)\x= = ". y = f(x) = 31 sec x + 18 tan x 31 sec x 18 tan x d dx -f(x)\ x= 1 *

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Q: f(x) 3 cos x 2 tan x - - f'(x) = f' 3 r()-

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Q: * /Q18 When x = acsc 0, ÷tan 0 = a

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Q: Let f(x) 4 cos x + 2 tan x f' (æ) = r(금)- f'

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Q: Let f(x) = tan '(sin(2a)) f'(r)

A: Given :f(x)=tan-1(sin(2x))

Q: If f(x) f'(x) = = COs x 4 tan x, then f'(4) = Check Answer

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Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

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Q: 1 Let f(x) = (5 sin x + 8 cos a)tan f'(x) =

A: NOTE: Refresh your page if you can't see any equations. . take derivative use the product rule for…

Q: let f(x) = { x3 tan-1(1/x) if x cannot = 0                 { 0 if x=0  determine whether f'(0)…

A: We can solve the given problem using differentiation of given function.

Q: sec x Given f(x) = 1. tan r then f'(x) = 1 – g(x) Find g(x). sec x g(x) =

A: We xan solve it by doing derivative by parts method.

Q: Let h(x) =tan(3x + 5). Then h' (4) is 3 sec² (17) 2 and h''(4) is

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Q: Wouldn't tan(x+pi)-(-sin(x)) yield tan(x+pi) + sin(x)) instead of tan(x+pi) - sin(x))?

A: Yes , there is a mistake on that question. I give u correct solution .  tan(x + π) - cos( x + (π/2))…

Q: Let h(x) = tan(3x + 4). Then h' (2) is and h'' (2) is

A: The function is given by hx = tan3x+4 To evaluate: The values of h'2 and h''(2)

Q: If f(x) = 7 tan-(2 sin(4)), f'(2) =|

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: tan a 5 f(x) = sec a find f' (x). Find f'().

A: We have to find the derivative of the given function

Q: Find, tan(x / 2)dx A) (1/2) sec (x/2)+c C) 2 sec (x/2)+c B) 2m sec(x/ 2)+c D) (1/2n sec(x/2) +c

A: Given that a integration of tan(x/2) and we solve it by using general formulas of integration. We…

Q: f(x) = 8 cos x 5 tan x.

A:

Q: Let f(x) = x² tan-'(8x) f'(x) =

A: Given: Now,

Q: If f(x) = 2 tan-'(8 sin(4x)), f'(x) =

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Q: If f(x) : f' (æ) = cos x – 6 tan x, then f'(2) =

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Q: Let f(x) = (7 sin x + 2 cos x)tan-lx f'(x) = %3D

A: topic - derivatives

Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Solve the equation (y - (cos x)^2)dx + (cos x) dy = 0

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Q: Find sec(x) and csc(x) if tan(x) =7 and sin(x) >0

A: The objective is to find sec(x) and csc(x) if tan(x) =7 and sin(x) >0

Q: If f(x) f'(æ) = cos x – 7 tan x, then

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Q: 1 If f(x) = 8 tan¯¹(8 sin(2x)), f'(x) =

A: Differentiate

Q: et f(x)=-11sin x+3 cos x f' (x)=?

A: f(x)=-11sin x+3 cos x this is given  we have to differentiate the function  dsinx/dx = cosx…

Q: If f(x) f'(x)= = 3x sin x cos x, find Find f'(5): =

A: 1) f(x)=3 sinx cosx 2) f(x)=8cosx+6tanx.

Q: Let f(x) tan-(cos(32)) f'(x) =

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Q: Let f (x) = (10x + 6)(x – tan x). Then %3D - f'(x) =

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Q: Differentiate: y = sec(5a- 3x) %3D O y' = - (1522 -3) sec(5r-3r) tan(5a-3r) %3D O y' = (152- 3) sec2…

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