Show that_(csc(x)) = −csc(x) cot(x). dx d (csc(x)) = dx || = dx sin²(x) 1 sin(x) 1 = = -csc(x) cot(x) | ) ‹0) – ¹([ sin²(x) sin(x)

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Q: If f(x) = = sin (3 – x), then f'(0) O 6 sin 3 cos 3 O 6 cos 3 O -2 sin 3 cos 3 O -2 cos 3 -2 cos O 2…

A: f(x)=sin2(3-x)

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Q: 2. Find the 2nd derivative of sin (x²-1) y *2cos(x^2-1) 4x^2 tan(x^2-1) 2cos(x^2-1) + 4x^2…

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Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

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Q: f(x) = sec(x) tan(x), then f'(3t) =

A: First derivate then put the value

Q: (tan x) = fu. v dx = (sin x) = | -=-=dx = (cos x) = fe" dx = | (arcsinx) = sec x tan x dx = secx tan…

A: We have to find out derivative and integral

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A: A function is said to be well-conditioned at a point if small changes in the input result in small…

Q: Differentiate each function a) f(x) =sin'[ (tan (cos (x²)) ] b) g(x) =/ sec(x* +2x) c) h(x)=V5 +3x²…

A: As per our guidelines we need to solve only 3 subparts.please repost the remaining subparts as other…

Q: Differentiate y = In ( sin² (4x)). A y' = 8 tan (4x) y' = 8 cot (4x) y' = 8 csc2 (4x) sin (8x) y' =…

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Q: Let f(x) = - 9 cos (sin(x*)). Then f'(x) = Preview

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Q: Verify the equation

A: To establish the given trigonometric identity

Q: Let f(x) = tan ¹(sin(8x)) f'(x) = > Next Question

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Q: f(x)=x+sinx / x2+cosx f '(x)=?

A: Given function: Now,

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Q: F(x)=2x sin(x)Tan(x) find f'(x)

A: Use the concept of derivative of the form  f = uvw

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A: Given: f(x)=sinx.sin2x.sin3x

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A: The function is y=sin(3x2−4x+1)aim is to find the derivative of the given sin function

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Q: cscxdx 5+ cos²x sin²x

A: Evaluate: I=∫csc2x5+cos2xsin2xdx We know that, cos xsin x=cot x Then, we have I=∫csc2x5+cot2xdx

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A: Derivative of cosx is -sinx.

Q: CSCX -1 Differentlate: f(x) = secx A f'(x) = - csc2x+ sinx f(x) = sinx - sec²x C rx)=cosx-sec2x f(x)…

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Q: dx (Cosx) = -sin(x) Example 39: Use delta method to find the derivative of tanx with respect to x.

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Q: If f(x) = f'(x) = f'(1) = 5 sin x 3+ cos x then

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Q: If f(x) ƒ'(x) = f'(2) = 4 sin x 3 + cos x then

A: derivative

Q: O find fx) if CoSx @ £(x)=. Sin X O flx) = x-4CSC x+2 Cot X © f(x)= (x).cotx 3- COSX. CSCX

A: SOLUTION-

Q: Find f'(x) = = 4-5 sin(x) cos²(x) f(x) = -4 sin(x) + 5 cos(x)

A: Given : f(x)=-4sin(x)+5cos(x)   To Find : f'(x)

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Q: = If f(x) = f'(x) = ƒ'(5) = 4 tan x, then - sin(x)-4 sec² (x) Cos x

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Q: f(x) = 7 sinx+ 5 cos x

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Q: If f(x) = cos(x), what is f'(x) ? O -sin(x) O cos(x) O -cos(x) O sin(x)

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