When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.60-cm-tall object is 59.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated with a comma. [ΕΑΣΦΗ s₁.lv 120,2.40 Submit 3 Previous Answers Request Answer ? cm

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### Combination of Lenses in Optics

When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. 

**Example Scenario:**
- **Object Details:**
  - Height: 1.60 cm
  - Initial Position: 59.0 cm to the left of the first converging lens

- **Lens Details:**
  - First Lens: Focal length of 40.0 cm
  - Second Lens: Focal length of 60.0 cm, positioned 300 cm to the right of the first lens along the same optic axis

For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of [An Image of an Image](#).

### Problem Statement (Part A):

**Task:** Find the location and height of the image (\(I_1\)) formed by the lens with a focal length of 40.0 cm.

**Instructions:**
- Enter your answers in centimeters separated with a comma.

**Example Answer Format:**
```plaintext
s'_1, |y'_1| = [location], [height] cm
```

**Provided Answer:**
```
120, 2.40 cm
```

**Interface:**
- There are input fields to enter the calculated values.
- Options: Submit, Previous Answers, Request Answer. 

By working through the described problem, students can practice the application of lens equations and the principles of magnification in optics.
Transcribed Image Text:### Combination of Lenses in Optics When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. **Example Scenario:** - **Object Details:** - Height: 1.60 cm - Initial Position: 59.0 cm to the left of the first converging lens - **Lens Details:** - First Lens: Focal length of 40.0 cm - Second Lens: Focal length of 60.0 cm, positioned 300 cm to the right of the first lens along the same optic axis For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of [An Image of an Image](#). ### Problem Statement (Part A): **Task:** Find the location and height of the image (\(I_1\)) formed by the lens with a focal length of 40.0 cm. **Instructions:** - Enter your answers in centimeters separated with a comma. **Example Answer Format:** ```plaintext s'_1, |y'_1| = [location], [height] cm ``` **Provided Answer:** ``` 120, 2.40 cm ``` **Interface:** - There are input fields to enter the calculated values. - Options: Submit, Previous Answers, Request Answer. By working through the described problem, students can practice the application of lens equations and the principles of magnification in optics.
### Part B

#### Question:
\( I_1 \) is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.

#### Instruction:
Enter your answers in centimeters separated with a comma.

#### Input Box:
There is an input box where you can enter your answer as shown below:

\[
s_2, |y_2| = \underline{ \hspace{5cm}} \; \text{cm}
\]

**Example Entry:**
49.29, 116

#### Provided Answer:
49.29, 116

### Submission
To submit your answer, press the 'Submit' button.

### Additional Options
- **Previous Answers**: Click to review your previous answers.
- **Request Answer**: Click to request the correct answer if you are unable to solve the problem.
Transcribed Image Text:### Part B #### Question: \( I_1 \) is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. #### Instruction: Enter your answers in centimeters separated with a comma. #### Input Box: There is an input box where you can enter your answer as shown below: \[ s_2, |y_2| = \underline{ \hspace{5cm}} \; \text{cm} \] **Example Entry:** 49.29, 116 #### Provided Answer: 49.29, 116 ### Submission To submit your answer, press the 'Submit' button. ### Additional Options - **Previous Answers**: Click to review your previous answers. - **Request Answer**: Click to request the correct answer if you are unable to solve the problem.
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