A lens located in the y-z plane at x = 0 forms an image of anarrow at x = x₂ = 101.3 cm. The tip of the object arrow islocated at (x,y) = (x₁, Y₁1) = (-49.9 cm, 5.32 cm). The index ofrefraction of the lens is n = 1.49.1) What is flens, the focal length of the lens? If the lens is converging flens is positive. It the lens is diverging, flens isnegative.cmSubmit2) What is y₂, the y-coordinate of the image of the tip of the arrow?cm SubmitVirtual and uprightVirtual and inverted(X₁,Y₁)3) The lens is a plano-convex lens. What is Rens, the radius of curvature of the convex side of the lens?cm SubmitX24) The object arrow is now moved to x = x1,new = -17.4 cm. What is X2,new, the new x-coordinate of the image of thearrow?cm Submit5) Is the new image of the arrow real or virtual? Is it upright or inverted?O Real and uprightReal and invertedX++++

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Answered: A lens located in the y-z plane at x =…

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A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x₂ = 101.3 cm. The tip of the object arrow is located at (x,y) = (x₁, Y₁) = (-49.9 cm, 5.32 cm). The index of refraction of the lens is n = 1.49. (X,Yi).