A ray of light is incident upon a surface of a block of transparent material, as shown in the figure. The material outside the block (n₁ =1) is air. The block's material has an index of refraction n₂ = 1.48. The angle of incidence 0₁ = 51.0 degrees. Note that this angle is measured relative to the surface normal (the dotted line perpendicular to the surface). What is the angle of reflection (0₁')? 0₁' = degrees Part of the ray is refracted upon entering the material. What is the angle of refraction within the material (0₂)? 0₂ = degrees What would the block's index of refraction need to become in order for the angle of refraction (0₂) on wh riginally?

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A ray of light is incident upon a surface of a block of transparent material, as shown in the figure.
The material outside the block (n₁ =1) is air. The block's material has an index of refraction n₂
1.48. The angle of incidence 8₁ = 51.0 degrees. Note that this angle is measured relative to the
surface normal (the dotted line perpendicular to the surface). What is the angle of reflection (0₁')?
0₁' =
degrees
Part of the ray is refracted upon entering the material. What is the angle of refraction within the
material (0₂)?
0₂ =
degrees
What would the block's index of refraction need to become in order for the angle of refraction (02)
to be 2 degrees less than what it was originally?
New n₂ =
n₁
n₂
0₁'
reflected ray
refracted ray
:0₂
Transcribed Image Text:A ray of light is incident upon a surface of a block of transparent material, as shown in the figure. The material outside the block (n₁ =1) is air. The block's material has an index of refraction n₂ 1.48. The angle of incidence 8₁ = 51.0 degrees. Note that this angle is measured relative to the surface normal (the dotted line perpendicular to the surface). What is the angle of reflection (0₁')? 0₁' = degrees Part of the ray is refracted upon entering the material. What is the angle of refraction within the material (0₂)? 0₂ = degrees What would the block's index of refraction need to become in order for the angle of refraction (02) to be 2 degrees less than what it was originally? New n₂ = n₁ n₂ 0₁' reflected ray refracted ray :0₂
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